What is the y-intercept of the graph of the line given by the equation 3y + 4x = 15?%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A5%0D%0A5%0D%0A%0D%0A4%0D%0A4%0D%0A%0D%0A3%0D%0A3%0D%0A%0D%0A–
To find the y-intercept of the line, we need to set x = 0 and solve for y.
When x = 0, we have:
3y + 4(0) = 15
3y = 15
y = 5
So the y-intercept of the line given by the equation 3y + 4x = 15 is 5.
To find the y-intercept of the line, we need to set x to 0 and solve for y in the equation 3y + 4x = 15.
Plugging in x = 0, we have:
3y + 4(0) = 15
Simplifying further:
3y + 0 = 15
3y = 15
Dividing both sides by 3:
y = 5
Therefore, the y-intercept of the line given by the equation 3y + 4x = 15 is 5.
To find the y-intercept of a line, we need to make x = 0 in the equation of the line and solve for y.
Given the equation 3y + 4x = 15, we substitute x = 0 into the equation:
3y + 4(0) = 15
3y = 15
y = 15 / 3
y = 5
Therefore, the y-intercept of the line is 5.