14 N
Box
8 N
Which change in force would stop this box from
moving?
(1 point)
adding 6 N of force pulling to the left
subtracting 8 N of force pulling to the right
adding 6 N of force pulling to the right
subtracting 8 N of force pulling to the left
Adding 6 N of force pulling to the right would stop the box from moving.
To stop the box from moving, you would need to apply a force in the opposite direction of the net force acting on the box. In this case, the net force acting on the box is the difference between the forces pulling to the right and the forces pulling to the left.
Given that the box is currently experiencing a net force of 14 N to the right (8 N pulling to the right and 6 N pulling to the left), the force needed to stop the box from moving would be equal to 14 N to the left.
Therefore, subtracting 8 N of force pulling to the left would be the change in force that would stop this box from moving.
To determine which change in force would stop the box from moving, we need to consider the net force acting on the box.
The net force is the vector sum of all the forces acting on the object. In this case, there are two forces acting on the box: a force of 14 N pulling to the right and a force of 8 N pulling to the left.
To stop the box from moving, we need to make the net force on the box zero. This means that the force pulling to the right should be equal in magnitude and opposite in direction to the force pulling to the left.
Let's analyze the options:
1) Adding 6 N of force pulling to the left: This would increase the force pulling to the left to 14 N + 6 N = 20 N. The net force would be 20 N - 14 N = 6 N to the left. The box would still move to the right, so this option doesn't stop the box from moving.
2) Subtracting 8 N of force pulling to the right: This would decrease the force pulling to the right to 14 N - 8 N = 6 N. The net force would be 6 N - 8 N = -2 N to the left. The box would still move to the right, though at a slower speed. This option doesn't stop the box from moving either.
3) Adding 6 N of force pulling to the right: This would increase the force pulling to the right to 14 N + 6 N = 20 N. The net force would be 20 N - 8 N = 12 N to the right. This option increases the net force to the right, which would accelerate the box's motion to the right. It doesn't stop the box from moving.
4) Subtracting 8 N of force pulling to the left: This would decrease the force pulling to the left to 8 N - 8 N = 0 N. The net force would be 14 N - 0 N = 14 N to the right. This option makes the net force to the right equal to the force to the right, resulting in a net force of zero. Therefore, this is the change in force that would stop the box from moving.
In conclusion, subtracting 8 N of force pulling to the left would stop the box from moving.