The distance between Greenville and Charleston is 4.5 inches on a map. If the map scale is 1 inch = 30 miles, what is the actual distance between the towns?
If 1 inch on the map is equal to 30 miles, then the distance of 4.5 inches on the map is equal to 4.5 x 30 = <<4.5*30=135>>135 miles. Answer: \boxed{135}.
To find the actual distance between the towns, we need to determine the ratio between inches on the map and miles in real life.
Given: The map scale is 1 inch = 30 miles.
We know that the distance between Greenville and Charleston on the map is 4.5 inches.
To calculate the actual distance, we need to multiply the distance on the map by the scale factor:
Actual distance = Distance on map × Scale factor
Distance on map = 4.5 inches
Scale factor = 30 miles/1 inch
Substituting the values:
Actual distance = 4.5 inches × (30 miles/1 inch)
Simplifying:
Actual distance = 4.5 × 30 miles
Actual distance = 135 miles
Therefore, the actual distance between Greenville and Charleston is 135 miles.
To find the actual distance between Greenville and Charleston, we need to use the map scale.
Given that 1 inch on the map represents 30 miles, we can set up a proportion to solve for the actual distance:
(1 inch) / (30 miles) = (4.5 inches) / (x miles)
Cross-multiplying, we get:
1 * x miles = 30 miles * 4.5 inches
Simplifying the right side:
x miles = 135 miles
Therefore, the actual distance between Greenville and Charleston is 135 miles.