Find the zero of the given function:
f(x) = -1/3x + 2
To find the zero of the function f(x) = -1/3x + 2, we set f(x) equal to zero and solve for x:
0 = -1/3x + 2
To isolate x, we subtract 2 from both sides:
-2 = -1/3x
Next, we multiply both sides by -3 to get rid of the fraction:
6 = x
Therefore, the zero of the function is x = 6.
To find the zero of a function, we need to solve the equation f(x) = 0.
For the given function f(x) = -1/3x + 2, we have:
-1/3x + 2 = 0
To solve for x, let's isolate x on one side of the equation.
First, we'll subtract 2 from both sides:
-1/3x = -2
To get rid of the fraction, we'll multiply both sides of the equation by -3 (the reciprocal of -1/3):
-3 * (-1/3x) = -3 * (-2)
This simplifies to:
x = 6
Therefore, the zero of the function f(x) = -1/3x + 2 is x = 6.
To find the zero of a function, we need to find the value of x where the function equals zero. In other words, we are looking for the x-coordinate of the point where the graph of the function intersects the x-axis.
In this case, the given function is f(x) = -1/3x + 2. To find the zero, we need to set the function equal to zero and solve for x.
Setting f(x) = 0, we have the equation:
-1/3x + 2 = 0
To solve this equation for x, we need to isolate the variable x. Let's start by subtracting 2 from both sides of the equation:
-1/3x = -2
Now, to get rid of the coefficient -1/3 in front of x, we can multiply both sides of the equation by -3. This will give us:
(-3)(-1/3x) = (-3)(-2)
x = 6
So, the zero of the given function f(x) = -1/3x + 2 is x = 6