A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest?(1 point)
Responses
10 N
10 N
98 N
98 N
9.8 N
9.8 N
1.02 N
The normal force acting on the stone, keeping it at rest, is equal in magnitude and opposite in direction to the gravitational force acting on it. Therefore, the normal force is equal to the weight of the stone, which can be calculated using the formula:
Weight = mass x acceleration due to gravity
Weight = 10 kg x 9.8 m/s^2
Weight = 98 N
So, the correct answer is 98 N.
The normal force acting on the stone can be calculated using the formula:
Normal force = mass * acceleration due to gravity
Given that the mass of the stone is 10 kg and the acceleration due to gravity is 9.8 m/s^2, we can substitute these values into the formula:
Normal force = 10 kg * 9.8 m/s^2
Normal force = 98 N
So, the correct answer is 98 N.
To determine the normal force acting on an object, you need to apply Newton's second law of motion. Newton's second law states that the net force on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the stone is at rest, the acceleration is zero.
The formula for calculating the normal force is:
Normal force = mass x acceleration due to gravity
Given:
Mass of the stone = 10 kg
Acceleration due to gravity = 9.8 m/s^2
Substituting the values into the formula:
Normal force = 10 kg x 9.8 m/s^2
Normal force = 98 N
So, the correct answer is 98 N.