The incoming 6th grade class has a choice between band or choir as an elective. There are four times as many seats in the chair as there are in band. How many students can choose band if there is a total of 250 students?
Let b be the number of students who choose band and c be the number of students who choose choir. We know that b + c = 250 and c = 4 * b.
Substituting the second equation into the first equation, we get b + 4 * b = 250
Combining like terms, we get 5 * b = 250
Dividing both sides by 5, we get b = 50. Answer: \boxed{50}.
To find out how many students can choose band, we first need to determine the number of seats available in each elective. Let's represent the number of seats in band as 'b'.
Given that there are four times as many seats in choir as there are in band, the number of seats in choir is 4b.
We know that the total number of students is 250, so the sum of the number of students in band and choir must equal 250.
Therefore, we can write the equation:
b + 4b = 250
Combining like terms, we have:
5b = 250
To solve for 'b', we divide both sides of the equation by 5:
b = 250 / 5
b = 50
Therefore, there are 50 seats available in band. Since each seat represents one student, 50 students can choose band as their elective.
To determine how many students can choose band, we need to find the number of seats in band and the number of seats in choir.
Let's assume the number of seats in band is x.
According to the given information, the number of seats in choir is four times the number of seats in band. So, the number of seats in choir is 4x.
The total number of students in the incoming 6th grade class is 250. Therefore, the total number of seats in both band and choir is x + 4x = 5x.
We can set up the equation: 5x = 250.
Dividing both sides of the equation by 5, we find:
x = 250 / 5 = 50.
Therefore, there are 50 seats in band.
Since each seat represents one student, the number of students who can choose band is 50.