Identify the vertex of y=−2(x−13)2+47
.(1 point)
Responses
(26,47)
left parenthesis 26 comma 47 right parenthesis
(−2,47)
left parenthesis negative 2 comma 47 right parenthesis
(13,47)
left parenthesis 13 comma 47 right parenthesis
(−13,47)
(13,47)
To identify the vertex of the quadratic function y = -2(x-13)^2 + 47, we need to understand the formula for the vertex of a quadratic equation in the standard form, y = a(x-h)^2 + k.
In this equation, a is the coefficient of x^2, h represents the horizontal shift of the parabola (vertex x-coordinate), and k represents the vertical shift (vertex y-coordinate).
Comparing our original equation to the standard form, we can determine that:
a = -2
h = 13
k = 47
Therefore, the vertex of the quadratic function y = -2(x-13)^2 + 47 is (13, 47).
The vertex form of the equation is: y = a(x-h)^2 + k, where (h, k) represents the vertex. In this case, the equation is y = -2(x - 13)^2 + 47.
Comparing with the vertex form, we can see that h = 13 and k = 47.
Therefore, the vertex is (13, 47).