What needs to be done in order to balance this equation?
HCl + Ba → BaCl2 + H2
Responses
It is already balanced.
It is already balanced.
Place a 2 in front of the HCl.
Place a 2 in front of the upper case H C lower case l .,
Place a 2 in front of the HCl and a 2 in front of the Ba.
Place a 2 in front of the upper case H C lower case l and a 2 in front of the upper case B lower case a .,
Place a 2 in front of the Ba.
Place a 2 in front of the HCl and a 2 in front of the Ba.
To balance the equation HCl + Ba → BaCl2 + H2, you will need to:
1. Place a 2 in front of the HCl:
2HCl + Ba → BaCl2 + H2
2. Place a 2 in front of the Ba:
2HCl + 2Ba → BaCl2 + H2
Therefore, the balanced equation is 2HCl + 2Ba → BaCl2 + H2.
To balance the given equation:
HCl + Ba -> BaCl2 + H2
Count the number of atoms on each side of the equation.
On the left side, there is 1 H (hydrogen) atom, 1 Cl (chlorine) atom, and 1 Ba (barium) atom.
On the right side, there are 2 Cl (chlorine) atoms, 1 Ba (barium) atom, and 2 H (hydrogen) atoms.
Since the number of atoms on each side is not equal, we need to balance the equation.
Start by balancing the complex or polyatomic ions first. In this case, the Cl atom is part of the Cl2 molecule, so we need to balance the Cl atoms first.
To balance the Cl atoms, place a coefficient of 2 in front of HCl:
2 HCl + Ba -> BaCl2 + H2
Now, let's check the number of Cl atoms on each side. On the left side, there are 2 Cl atoms, and on the right side, there are 2 Cl atoms.
Next, let's balance the H (hydrogen) atoms. On the right side, there are 2 H atoms. To balance this, place a coefficient of 2 in front of H2:
2 HCl + Ba -> BaCl2 + 2 H2
Now, let's check the number of H atoms on each side. On the left side, there are 2 H atoms, and on the right side, there are also 2 H atoms.
Finally, let's check the number of Ba atoms on each side. On the left side, there is 1 Ba atom, and on the right side, there is also 1 Ba atom. The Ba atom is already balanced.
Therefore, the balanced equation is:
2 HCl + Ba -> BaCl2 + 2 H2