2t+8≥−4(t+1)
2t + 8 ≥ -4(t + 1)
Let's solve for t step by step:
First, distribute -4 to t + 1:
2t + 8 ≥ -4t - 4
Next, combine like terms on both sides of the equation:
2t + 4t + 8 ≥ -4
Simplify:
6t + 8 ≥ -4
Now, subtract 8 from both sides of the equation:
6t ≥ -12
Finally, divide both sides by 6 to solve for t:
t ≥ -2
Therefore, the solution to the inequality 2t + 8 ≥ -4(t + 1) is t ≥ -2.
To solve the inequality 2t + 8 ≥ -4(t + 1), we can follow these steps:
Step 1: Distribute the -4 on the right side of the inequality:
2t + 8 ≥ -4t - 4
Step 2: Combine like terms on both sides of the inequality:
6t + 8 ≥ -4
Step 3: Subtract 8 from both sides of the inequality:
6t ≥ -4 - 8
Simplifying further:
6t ≥ -12
Step 4: Divide both sides of the inequality by 6 (since the coefficient of t is 6):
t ≥ -12/6
Simplifying further:
t ≥ -2
Therefore, the solution to the inequality 2t + 8 ≥ -4(t + 1) is t ≥ -2.
To solve the inequality 2t + 8 ≥ -4(t + 1), we will apply the distributive property and basic algebraic operations to determine the value(s) of t that satisfy the inequality.
1. Distribute the -4 to the terms inside the parentheses:
2t + 8 ≥ -4t - 4
2. Combine like terms:
2t + 8 ≥ -4t - 4
(2t + 4t) + 8 ≥ -4
3. Combine the terms:
6t + 8 ≥ -4
4. Subtract 8 from both sides of the inequality:
6t + 8 - 8 ≥ -4 - 8
6t ≥ -12
5. Divide both sides of the inequality by 6:
6t/6 ≥ -12/6
t ≥ -2
Therefore, the solution to the inequality 2t + 8 ≥ -4(t + 1) is t ≥ -2.