Jeff had a lemonade stand and ended up with 5 times as much money at the end of the day than at the beginning of the day. He ended the day with $110. How much did he start with?
Responses
A $22$22
B $105$105
C $115$115
D $550
Let's say Jeff started with x dollars.
At the end of the day, he had 5 times as much money, so he had 5x dollars.
We're told that he ended the day with $110, so 5x = $110.
To solve for x, we divide both sides of the equation by 5: x = $110 / 5 = $<<110/5=22>>22.
Therefore, Jeff started the day with $22, so the answer is $\boxed{A}$
To solve this problem, we can use a simple equation. Let's assume Jeff started with an amount of money, let's call it "x".
According to the problem, Jeff ended the day with 5 times as much money as he started with, so we can write the equation:
5 * x = $110
To find the value of "x", we need to divide both sides of the equation by 5:
x = $110 / 5
Dividing $110 by 5 gives us $22.
Therefore, Jeff started the day with $22. So the correct answer is option A: $22.
To find out how much Jeff started with, we can divide the amount he ended up with by the number of times he had at the end of the day, which is 5.
So, we can set up the equation:
Amount at the beginning of the day = Amount at the end of the day / Number of times = $110 / 5
Simplifying this equation, we get:
Amount at the beginning of the day = $22
Therefore, Jeff started with $22.
So, the correct answer is A) $22.