The altitude of an airplane is decreasing at the rate of 40 ft./s. What is the change in the altitude of the airplane over a period of 16
We can solve this problem using the formula for average rate of change:
Average rate of change = (final value - initial value) / time
In this case, the initial value is the altitude of the airplane at the start, the final value is the altitude of the airplane 16 seconds later, and the time is 16 seconds.
Since the altitude is decreasing at a rate of 40 ft./s, the change in altitude over 16 seconds is (40 ft./s)(16 seconds) = 640 feet.
Therefore, the change in altitude of the airplane over a period of 16 seconds is 640 feet.
To find the change in altitude, we can use the formula:
Change in altitude = rate of change × time
Given that the rate of change is 40 ft./s and the time period is 16 seconds, we can substitute these values into the formula:
Change in altitude = 40 ft./s × 16 s
Calculating this, we get:
Change in altitude = 640 ft.
Therefore, the change in altitude of the airplane over a period of 16 seconds is 640 feet.
To find the change in altitude of the airplane over a specific period of time, we can multiply the rate of change (in this case, -40 ft./s since it is decreasing) by the duration of time (in this case, 16 seconds).
Change in altitude = rate of change × time
Change in altitude = -40 ft./s × 16 s
Multiplying -40 ft./s by 16 s gives us:
Change in altitude = -640 ft.
Therefore, the change in altitude of the airplane over a period of 16 seconds is -640 feet.