ON A GIVEN MORNING THE TEMP WAS 81F THE TEMP DROPPED 9F AN THEN ROSE 5F HOW MUCH DOEST THE TEMP OF 81
RISE 9
RISE 4
FALL 4
FALL 5
The temperature initially dropped 9F, so it would be 81 - 9 = 72F.
Then the temperature rose 5F, so it becomes 72 + 5 = 77F.
Therefore, the temperature of 81F falls by 4F.
To determine the net change in temperature from the initial value of 81°F, we'll subtract the temperature drops and add the temperature rises:
Initial temperature: 81°F
Drop 1: -9°F (81°F - 9°F = 72°F)
Rise 1: +5°F (72°F + 5°F = 77°F)
Therefore, the net change in temperature from 81°F is a decrease of 4°F.
To determine the change in temperature from 81°F given that it dropped 9°F and then rose 5°F, you need to perform some calculations.
Start with the initial temperature of 81°F.
First, the temperature dropped by 9°F. To find the new temperature, subtract 9 from 81:
81°F - 9°F = 72°F
Next, the temperature rose by 5°F. To find the final temperature, add 5 to 72:
72°F + 5°F = 77°F
Therefore, the temperature of 81°F dropped by 9°F and then rose by 5°F, resulting in a final temperature of 77°F.