Identify the vertex of y = 4(x - 25)^ - 61. (1 point)
O (4, -25)
O (-25, -61)
O (-100, -61)
O (25, -61)
The vertex form of a quadratic function is given by the equation y = a(x - h)^2 + k, where (h, k) is the vertex. Comparing this with the given equation y = 4(x - 25)^ - 61, we can see that the vertex is (25, -61).
Therefore, the correct answer is O (25, -61).
To identify the vertex of the equation y = 4(x - 25)^2 - 61, we can use the vertex form of a quadratic equation, y = a(x - h)^2 + k, where (h, k) represents the vertex.
Comparing this with the given equation, we can see that h = 25 and k = -61.
Therefore, the vertex is at point (25, -61).
The correct answer is O (25, -61).
To identify the vertex of the equation y = 4(x - 25)^2 - 61, we need to recall the vertex form of a quadratic equation: y = a(x - h)^2 + k. In this form, the vertex of the parabola is represented by the point (h, k).
In the given equation, we have y = 4(x - 25)^2 - 61. Comparing this with the vertex form, we see that the vertex is at the point (h, k) = (25, -61).
Therefore, the correct answer is O (25, -61).