Identify the vertex of y=−10(x+15)2−18 .(1 point)
Responses
(−150,−18)
left parenthesis negative 150 comma negative 18 right parenthesis
(15,−18)
left parenthesis 15 comma negative 18 right parenthesis
(−15,−18)
left parenthesis negative 15 comma negative 18 right parenthesis
(−10,−15)
None of the given responses are correct. Let's find the vertex using the formula.
The equation is in the form y = a(x-h)^2 + k, where (h, k) is the vertex.
In this case, a = -10, h = -15, and k = -18.
So, the vertex is (-15, -18).
Therefore, the correct response is (−15,−18).
To identify the vertex of the equation y = -10(x+15)^2 - 18, we can look at the equation in vertex form: y = a(x-h)^2 + k. In this form, the vertex of the parabola is represented by the point (h, k).
Comparing the given equation with the vertex form, we can see that h = -15 and k = -18. Therefore, the vertex of the parabola is (-15, -18).
Answer: (−15,−18)
To identify the vertex of the quadratic function y = -10(x+15)^2 - 18, we can use the vertex form of a quadratic function, which is given by the equation y = a(x-h)^2 + k, where (h, k) represents the coordinates of the vertex.
In this case, the given equation can be rewritten as y = -10(x+15)^2 - 18. Comparing this to the vertex form, we can see that h = -15 and k = -18.
Therefore, the vertex of the quadratic function is (-15, -18). So the correct answer is option (C): (−15,−18) or (left parenthesis negative 15 comma negative 18 right parenthesis).