2NaN3(s) -› 2Na(s) + 3N.(g)
This reaction produces nitrogen to inflate airbags in cars. Sodium Azide (NaNs) produces Nitrogen (N2) very quickly in a crash.How many moles of NaN, are needed to fill a 65 L airbag?
Assume the gas is produced at a temperature of 30 °C
To calculate the number of moles of NaN3 needed to fill a 65 L airbag, we need to use the ideal gas law equation:
PV = nRT
Where:
P = Pressure (assumed atmospheric pressure, which is 1 atm)
V = Volume
n = Number of moles
R = Ideal Gas Constant (0.0821 L.atm/mol.K)
T = Temperature (30 °C, which needs to be converted to Kelvin)
First, let's convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 30 °C + 273.15
T(K) = 303.15 K
Now, we can rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT
Plugging in the values:
P = 1 atm
V = 65 L
R = 0.0821 L.atm/mol.K
T = 303.15 K
n = (1 atm * 65 L) / (0.0821 L.atm/mol.K * 303.15 K)
n = 2.14329303551 moles
Therefore, approximately 2.14 moles of NaN3 are needed to fill a 65 L airbag.
To calculate the number of moles of NaN3 needed to fill a 65 L airbag, we can use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, let's convert the given temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 30 °C + 273.15
T(K) = 303.15 K
Next, let's calculate the pressure. The pressure is not given in the question, so we need to assume a pressure. Let's assume a typical airbag pressure of 2 atmospheres (atm).
Now we can rearrange the ideal gas law equation to solve for n:
n = PV / RT
Substituting the values into the equation:
P = 2 atm
V = 65 L
R = 0.0821 L.atm/mol.K
T = 303.15 K
n = (2 atm)(65 L) / (0.0821 L.atm/mol.K)(303.15 K)
n = 130 atm.L / (24.987 L.mol^-1.K^-1)
n ≈ 5.21 moles
Therefore, approximately 5.21 moles of NaN3 are needed to fill a 65 L airbag.
To find out the number of moles of NaN3 required to fill a 65 L airbag, we need to use the ideal gas law equation:
PV = nRT
Where:
P is the pressure of the gas (which we will assume to be atmospheric pressure at sea level: 1 atm)
V is the volume of the gas (65 L)
n is the number of moles of gas we want to find
R is the ideal gas constant (0.0821 L·atm/mol·K)
T is the temperature of the gas in Kelvin (30 °C = 273.15 K + 30 K = 303.15 K)
Rearranging the equation to solve for n:
n = PV / RT
Substituting the values, we have:
n = (1 atm)(65 L) / (0.0821 L·atm/mol·K)(303.15 K)
Calculating this expression will give us the number of moles of NaN3 required to fill the airbag.