The value of y is directly proportional to the value of x. When x = 9 y = 63
What is the value of y when x = 6
If y is directly proportional to x, we can set up a proportion using the given values:
x1/y1 = x2/y2
Substituting the given values:
9/63 = 6/y2
To find y2, we can cross-multiply:
9y2 = 6 * 63
9y2 = 378
Now, divide both sides by 9 to solve for y2:
y2 = 378/9
The value of y when x = 6 is 42.
To find the value of y when x = 6, we can use the concept of direct proportion.
We know that the value of y is directly proportional to the value of x. This means that for every increase or decrease in x, y will also increase or decrease by the same proportion.
Given that when x = 9, y = 63, we can set up a proportion to solve for y when x = 6:
x₁ / y₁ = x₂ / y₂
Substituting the values we have:
9 / 63 = 6 / y₂
Now, we cross-multiply and solve for y₂:
9 * y₂ = 6 * 63
9y₂ = 378
Dividing both sides by 9:
y₂ = 378 / 9
y₂ = 42
Therefore, when x = 6, y will be equal to 42.
To find the value of y when x = 6, we can use the concept of direct proportionality. In a direct proportion, the ratio between two variables remains constant. We can use this ratio to find the value of y when x = 6.
Given that y is directly proportional to x, we can write the proportion:
y/x = k
where k is the constant of proportionality.
To find the value of k, we can substitute the given values of x and y:
63/9 = k
Simplifying this equation, we find:
k = 7
Now that we have the constant of proportionality, we can substitute the given value of x = 6 into the proportion:
y/6 = 7
To find the value of y, we can solve for y by multiplying both sides of the equation by 6:
y = 42
Therefore, when x = 6, the value of y is 42.