charla wants to cover a certain rectangular area of her drive way with a picture using chalk if she complets 2/3 of the area in 1/2 how long will take her to complet the entire picture

If Charla completes 2/3 of the area in 1/2, it means that she completes 2/3 * 1/2 = 1/3 of the area in 1/2 an hour.

To complete the entire picture, it would take her 1/3 * 3 = 1 hour. Answer: \boxed{1}.

To find out how long it will take Charla to complete the entire picture, we need to find the ratio between the area she completed in 1/2 hour and the total area.

Let's assume the total area of the rectangular driveway is represented by A.

According to the given information, Charla completed 2/3 of the area in 1/2 hour. This means she completed (2/3)A in 1/2 hour.

To find the time it will take her to complete the entire picture, we can set up the following proportion:

(1/2 hour) / ((2/3)A) = x hours / A

To solve this proportion, we can cross-multiply:

(1/2) * A = ((2/3)A) * x

Now, let's simplify and solve for x:

A/2 = (2A/3) * x

3A = 4A * x

Divide both sides by 4A:

3/4 = x

Therefore, it will take Charla 3/4 hour to complete the entire picture.

To determine how long it will take Charla to complete the entire picture, we first need to understand the relationship between the fractions.

Charla completes 2/3 (two-thirds) of the area in 1/2 (one-half) of the time.

To find the remaining area that Charla needs to cover, we subtract the completed area (2/3) from the total area (1).

1 - 2/3 = 1/3

So, Charla needs to cover 1/3 (one-third) of the area.

Since she completes 2/3 in 1/2 of the time, we can set up a proportion to find the time it takes her to complete the remaining 1/3:

(2/3) / (1/2) = (1/3) / x

Cross-multiplying:

(2/3) * x = (1/3) * (1/2)

Multiplying both sides:

2x/3 = 1/6

To solve for x, we can multiply both sides by 3/2:

(2x/3) * (3/2) = (1/6) * (3/2)

2x/2 = 3/12

x = 3/12

Simplifying the fraction:

x = 1/4

So, it will take Charla 1/4 of the time it took her to complete 2/3 to finish the entire picture.