If Tums (CaCO3) is added to 25.0 mL of a solution that is 0.300 M in HCl, how many grams of CO2 gas are produced?
To determine the number of grams of CO2 gas produced, we need to first determine the number of moles of HCl in the solution, and then use stoichiometry to convert the moles of HCl to moles of CO2 gas, and finally convert to grams of CO2 gas using the molar mass of CO2.
The balanced chemical equation for the reaction between HCl and CaCO3 is:
2HCl + CaCO3 -> CaCl2 + CO2 + H2O
From the equation, we can see that 2 moles of HCl react with 1 mole of CaCO3 to produce 1 mole of CO2 gas.
First, let's calculate the number of moles of HCl in the solution:
Moles of HCl = concentration of HCl x volume of solution
Moles of HCl = 0.300 mol/L x 0.0250 L
Moles of HCl = 0.0075 mol
According to the stoichiometry of the balanced equation, we know that 2 moles of HCl react with 1 mole of CaCO3 to produce 1 mole of CO2 gas, so the number of moles of CO2 gas produced is also 0.0075 mol.
Lastly, let's convert moles of CO2 gas to grams of CO2 gas using the molar mass of CO2:
Molar mass of CO2 = (12.01 g/mol) + (2 * 16.00 g/mol)
Molar mass of CO2 = 44.01 g/mol
Grams of CO2 gas = moles of CO2 gas x molar mass of CO2
Grams of CO2 gas = 0.0075 mol x 44.01 g/mol
Grams of CO2 gas = 0.3308 g
Therefore, approximately 0.3308 grams of CO2 gas are produced.
To determine the number of grams of CO2 gas produced when Tums (CaCO3) is added to a solution of HCl, we first need to write out the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between CaCO3 and HCl is:
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)
From the balanced equation, we can see that 1 mole of CaCO3 reacts with 2 moles of HCl to produce 1 mole of CO2.
Step 1: Calculate the number of moles of HCl.
Given: Volume of HCl solution = 25.0 mL
Concentration of HCl solution = 0.300 M
Step 1.1: Convert the volume of HCl solution to liters.
25.0 mL × (1 L / 1000 mL) = 0.0250 L
Step 1.2: Calculate the number of moles of HCl.
Number of moles = Volume of solution (in liters) × Concentration of solution
Number of moles = 0.0250 L × 0.300 mol/L = 0.00750 mol of HCl
Step 2: Use stoichiometry to determine the moles of CO2 produced.
From the balanced equation, we know that 1 mole of CaCO3 produces 1 mole of CO2.
Therefore, the number of moles of CO2 produced is also 0.00750 mol.
Step 3: Calculate the mass of CO2.
To calculate the mass of CO2, we need to use the molar mass of CO2, which is approximately 44.01 g/mol.
Step 3.1: Calculate the mass of CO2.
Mass = Number of moles × Molar mass
Mass = 0.00750 mol × 44.01 g/mol = 0.3308 g
Therefore, when Tums (CaCO3) is added to a 25.0 mL solution that is 0.300 M in HCl, approximately 0.3308 grams of CO2 gas are produced.
To solve this problem, we need to use stoichiometry and the balanced chemical equation for the reaction between HCl and CaCO3.
The balanced chemical equation for the reaction is:
2 HCl(aq) + CaCO3(s) -> CaCl2(aq) + CO2(g) + H2O(l)
From the balanced equation, we can see that 2 moles of HCl react with 1 mole of CaCO3 to produce 1 mole of CO2 gas.
First, let's calculate the number of moles of HCl in the solution:
moles of HCl = (concentration of HCl) x (volume of solution in liters)
= (0.300 M) x (25.0 mL / 1000 mL/L)
= 0.0075 moles
Since the stoichiometric ratio between HCl and CO2 is 2:1, we can determine the moles of CO2 produced:
moles of CO2 = (moles of HCl) / 2
= 0.0075 moles / 2
= 0.00375 moles
Finally, we can calculate the mass of CO2 produced using its molar mass:
mass of CO2 = (moles of CO2) x (molar mass of CO2)
= 0.00375 moles x 44.01 g/mol
= 0.16594 g
Therefore, approximately 0.16594 grams of CO2 gas are produced when Tums (CaCO3) is added to 25.0 mL of a solution that is 0.300 M in HCl.