Identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3.
(1 point)
Responses
vertex: (2, –3); axis of symmetry: x = 2
vertex: (2, –3); axis of symmetry: x = 2
vertex: (–2, –3); axis of symmetry: x = –2
vertex: (–2, –3); axis of symmetry: x = –2
vertex: (2, 3); axis of symmetry: x = 2
vertex: (2, 3); axis of symmetry: x = 2
vertex: (–2, 3); axis of symmetry: x = –2
The correct answer is:
vertex: (-2, -3); axis of symmetry: x = -2
The correct answer is: vertex: (-2, -3); axis of symmetry: x = -2
To identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 - 3, we can use the standard form of a quadratic function: y = a(x - h)2 + k.
Comparing this standard form with the given function, we can determine the values of h and k. In this case, h = -2 and k = -3.
The vertex of a quadratic function is given by the coordinates (h, k), so the vertex of the given function is (h, k) = (-2, -3).
The axis of symmetry of a quadratic function is the vertical line that passes through the vertex. The equation of the axis of symmetry is x = h, so in this case, the axis of symmetry is x = -2.
Therefore, the correct answer is:
- vertex: (-2, -3)
- axis of symmetry: x = -2