Suppose R = {2, 4, 6, 8, 10, 12, 14} and D = {3, 6, 9, 12, 15, 18, 21}.

What is r half circle d?

The term "r half circle d" is not clear and does not correspond to any standard mathematical notation or operation. It is possible that this is a notation specific to the context or question you are referring to. Can you please provide more information or clarify your question?

i cant type the symbol but it is a half circle the opening down

If you are referring to the symbol "⊂" which represents a subset, then "r half circle d" would mean the subset of elements in R that are also in D. In this case, the subset would consist of the common elements between R and D, which are {6, 12}.

So, r half circle d = {6, 12}.

more of an n shape

If you are referring to the symbol "∩" which represents the intersection of sets, then "r half circle d" would mean the intersection of R and D.

The intersection of R = {2, 4, 6, 8, 10, 12, 14} and D = {3, 6, 9, 12, 15, 18, 21} would be the set of elements that are common to both R and D. In this case, the intersection set would be {6, 12}.

So, r half circle d = {6, 12}.

thank you sorry i didnt say it right the first time

No problem! I'm glad I could help clarify. If you have any more questions, feel free to ask!

one more question

A student scored 75 and 92 on some tests. Write and solve an inequality to find values for the third test score that would give her an average between 80 and 90 inclusive

Let x be the score on the third test.

To find the average between 80 and 90 inclusive, we can set up the inequality:

(75 + 92 + x)/3 ≥ 80 and (75 + 92 + x)/3 ≤ 90

Simplifying the inequality, we get:

(167 + x)/3 ≥ 80 and (167 + x)/3 ≤ 90

Now, we can solve each inequality separately:

(167 + x)/3 ≥ 80

Multiplying both sides of the inequality by 3, we get:

167 + x ≥ 240

Subtracting 167 from both sides of the inequality, we get:

x ≥ 73

(167 + x)/3 ≤ 90

Multiplying both sides of the inequality by 3, we get:

167 + x ≤ 270

Subtracting 167 from both sides of the inequality, we get:

x ≤ 103

Therefore, the third test score must be between 73 and 103 (inclusive) in order to have an average between 80 and 90 inclusive.

i just hope you know i cheated