The size of a cell is typically found by capturing an image under a microscope then using software to measure its diameter. Two cells are measured using this method:
Cell G: 9, point, 2, 3, times, 10, to the power minus 39.23×10
−3
centimeters
Cell H: 4, point, 2, times, 10, to the power minus 44.2×10
−4
centimeters
How much larger is the diameter of cell G than the diameter of cell H? Express your answer using scientific notation.
Answer
Attempt 1 out of 2
Answer:
times, 10×10
centimeters
To find the difference in diameter between cell G and cell H, we need to subtract the diameter of cell H from the diameter of cell G.
The diameter of cell G is 9.2 × 10^(-39.23) cm.
The diameter of cell H is 4.2 × 10^(-44.2) cm.
To subtract these values, we need to make sure the exponents are the same. In this case, we can convert both values to the same exponent by adjusting the decimal place:
9.2 × 10^(-39.23) cm = 0.92 × 10^(-38.23) cm
4.2 × 10^(-44.2) cm = 0.42 × 10^(-43.2) cm
Now we can subtract the values:
0.92 × 10^(-38.23) cm - 0.42 × 10^(-43.2) cm = (0.92 - 0.42) × 10^(-38.23) cm
Simplifying the subtraction:
0.50 × 10^(-38.23) cm = 5.0 × 10^(-39.23) cm
Therefore, the diameter of cell G is 5.0 × 10^(-39.23) cm larger than the diameter of cell H.
The approximate average distances from the sun to Venus and Mercury are listed below:
Venus: 1, point, 0, 8, times, 10, to the power 81.08×10
8
kilometers
Mercury: 5, point, 7, 9, times, 10, to the power 75.79×10
7
kilometers
How much closer to the sun is Mercury? Express your answer using scientific notation.
Answer
Attempt 1 out of 2
Answer:
times, 10×10
kilometers
To find out how much closer Mercury is to the sun compared to Venus, we need to subtract the average distance of Venus from the average distance of Mercury.
The average distance of Venus from the sun is 1.08 × 10^8 kilometers.
The average distance of Mercury from the sun is 5.79 × 10^7 kilometers.
To subtract these values, we need to make sure the exponents are the same. In this case, we can convert both values to the same exponent by adjusting the decimal place:
1.08 × 10^8 kilometers = 10.8 × 10^7 kilometers
5.79 × 10^7 kilometers = 57.9 × 10^6 kilometers
Now we can subtract the values:
10.8 × 10^7 kilometers - 57.9 × 10^6 kilometers = (10.8 - 57.9) × 10^7 kilometers
Simplifying the subtraction:
-47.1 × 10^7 kilometers = -4.71 × 10^8 kilometers
Therefore, Mercury is approximately 4.71 × 10^8 kilometers closer to the sun compared to Venus.
pls try again
Apologies for the mistake. Let's try again:
To find out how much closer Mercury is to the sun compared to Venus, we need to subtract the average distance of Venus from the average distance of Mercury.
The average distance of Venus from the sun is 1.08 × 10^8 kilometers.
The average distance of Mercury from the sun is 5.79 × 10^7 kilometers.
To subtract these values, we need to make sure the exponents are the same. In this case, we can convert both values to the same exponent by adjusting the decimal place:
1.08 × 10^8 kilometers = 10.8 × 10^7 kilometers
5.79 × 10^7 kilometers = 57.9 × 10^6 kilometers
Now we can subtract the values:
10.8 × 10^7 kilometers - 57.9 × 10^6 kilometers = (10.8 - 5.79) × 10^7 kilometers
Simplifying the subtraction:
5.01 × 10^7 kilometers = 5.01 × 10^7 kilometers
Therefore, Mercury is approximately 5.01 × 10^7 kilometers closer to the sun compared to Venus.
How many times greater is 6, point, 7, 5, times, 10, to the power minus 46.75×10
−4
than 4, point, 5, times, 10, to the power minus 84.5×10
−8
? Express your answer using either standard notation or scientific notation.
Answer
Attempt 1 out of 2
Standard Notation or Scientific notation
Answer:
To find out how many times greater the first value is compared to the second value, we need to divide the first value by the second value.
The first value is 6.75 × 10^(-46.75).
The second value is 4.5 × 10^(-84.5).
To divide these values, we can subtract the exponents and divide the coefficients:
(6.75 / 4.5) × 10^(-46.75 - (-84.5)) = 1.5 × 10^(37.75)
Therefore, the first value is 1.5 × 10^37.75 times greater than the second value.
The size of a cell is typically found by capturing an image under a microscope then using software to measure its diameter. Two cells are measured using this method:
Cell D: 4, point, 6, 1, times, 10, to the power minus 34.61×10
−3
centimeters
Cell E: 5, point, 5, times, 10, to the power minus 45.5×10
−4
centimeters
What's the difference between the diameters of the two cells? Express your answer using either standard notation or scientific notation.
Answer
Attempt 1 out of 2
Standard Notation
Answer:
centimeters
To find the difference between the diameters of cell D and cell E, we need to subtract the diameter of cell E from the diameter of cell D.
The diameter of cell D is 4.61 × 10^(-34.61) cm
The diameter of cell E is 5.5 × 10^(-45.5) cm
To subtract these values, we need to make sure the exponents are the same. In this case, we can convert both values to the same exponent by adjusting the decimal place:
4.61 × 10^(-34.61) cm = 46.1 × 10^(-35.61) cm
5.5 × 10^(-45.5) cm = 55 × 10^(-45.5) cm
Now we can subtract the values:
46.1 × 10^(-35.61) cm - 55 × 10^(-45.5) cm = (46.1 - 55) × 10^(-35.61) cm
Simplifying the subtraction:
-8.9 × 10^(-35.61) cm
Therefore, the difference between the diameters of the two cells is approximately -8.9 × 10^(-35.61) cm.