The size of a cell is typically found by capturing an image under a microscope then using software to measure its diameter. Two cells are measured using this method:
Cell H: 9, point, 4, 7, times, 10, to the power minus 39.47×10
−3
centimeters
Cell K: 8, point, 5, times, 10, to the power minus 48.5×10
−4
centimeters
How many times larger is the diameter of cell H than the diameter of cell K? Write your answer in standard notation, rounding to the nearest tenth.
Answer
Attempt 1 out of 2
Answer:
To find the ratio between the diameters of cell H and cell K, we can divide the diameter of cell H by the diameter of cell K.
The diameter of cell H is 9.47×10^-3 centimeters.
The diameter of cell K is 8.5×10^-4 centimeters.
Dividing the two, we get:
9.47×10^-3 / 8.5×10^-4 ≈ 11.13
Therefore, the diameter of cell H is approximately 11.13 times larger than the diameter of cell K.
The size of a cell is typically found by capturing an image under a microscope then using software to measure its diameter. Two cells are measured using this method:
Cell H: 9, point, 4, 7, times, 10, to the power minus 39.47×10
−3
centimeters
Cell K: 8, point, 5, times, 10, to the power minus 48.5×10
−4
centimeters
How many times larger is the diameter of cell H than the diameter of cell K? Write your answer in standard notation, rounding to the nearest tenth.
Answer:
To find the ratio between the diameters of cell H and cell K, we can divide the diameter of cell H by the diameter of cell K.
The diameter of cell H is 9.47×10^-3 centimeters.
The diameter of cell K is 8.5×10^-4 centimeters.
Dividing the two, we get:
(9.47×10^-3) / (8.5×10^-4) ≈ 11.12
Therefore, the diameter of cell H is approximately 11.1 times larger than the diameter of cell K.
At a certain lab, the average mass of one ant is measured to be 2, point, 9, times, 10, to the power minus 62.9×10
−6
kilograms. Use scientific notation to express the mass of 6060 ants.
Answer
Attempt 1 out of 2
Answer:
times, 10×10
kilograms
To find the mass of 6060 ants, we can multiply the average mass of one ant by the number of ants.
The average mass of one ant is 2.9×10^-6 kilograms.
Multiplying by 6060, we get:
(2.9×10^-6) * 6060 = 1.7574×10^-2 kilograms
Therefore, the mass of 6060 ants is approximately 1.7574×10^-2 kilograms.
At a certain lab, the average mass of one ant is measured to be 2, point, 9, times, 10, to the power minus 62.9×10
−6
kilograms. Use scientific notation to express the mass of 6060 ants.
Answer:
times, _____×10^-----
kilograms
To find the mass of 6060 ants, we can multiply the average mass of one ant by the number of ants.
The average mass of one ant is 2.9×10^-6 kilograms.
Multiplying by 6060, we get:
(2.9×10^-6) * 6060 = 1.7574×10^-2 kilograms
Therefore, the mass of 6060 ants is approximately 1.7574×10^-2 kilograms.
pls try again
Apologies for the confusion. Let's calculate the mass of 6060 ants using scientific notation.
The average mass of one ant is 2.9×10^-6 kilograms.
To find the mass of 6060 ants, we can multiply the average mass by the number of ants:
(2.9×10^-6 kg) * 6060 = 17.574 × 10^0 kilograms
Since the exponent is 0, we can drop it and write the answer in standard notation:
The mass of 6060 ants is approximately 17.574 kilograms.