A metal mass of 5 grams absorbs 240 J of heat temperature increases Temperature increases by 200 0 C. What is the specific heat?
The specific heat can be calculated using the formula:
specific heat = Q / (m * ΔT),
where Q is the heat absorbed, m is the mass of the metal, and ΔT is the change in temperature.
Given:
Q = 240 J,
m = 5 grams (which can be converted to 0.005 kg),
ΔT = 200°C (which can be converted to 200 K, as the change in temperature is the same in Kelvin and Celsius).
Let's plug in the values into the formula:
specific heat = 240 J / (0.005 kg * 200 K) = 240 J / 1 kg * 200 K = 0.24 J/(kg · K).
Therefore, the specific heat of the metal is 0.24 J/(kg · K).
To find the specific heat, we can use the equation:
Q = mcΔT
Where:
Q = heat absorbed (in Joules)
m = mass (in grams)
c = specific heat
ΔT = change in temperature (in degrees Celsius)
Given:
Q = 240 J
m = 5 g
ΔT = 200 °C
Converting the mass from grams to kilograms:
m = 5 g = 0.005 kg
Substituting the given values into the equation:
240 J = (0.005 kg) * c * (200 °C)
Simplifying the equation:
240 J = 0.001 kg c * 200 °C
Dividing both sides of the equation by 0.001 kg * 200 °C:
c = 240 J / (0.001 kg * 200 °C)
Calculating:
c = 1.2 J / (kg * °C)
Therefore, the specific heat of the metal is 1.2 J / (kg * °C).
To find the specific heat of a substance, you need to use the formula:
Q = mcΔT
Where:
Q = heat absorbed (in joules)
m = mass of the substance (in grams)
c = specific heat (in joules/gram degrees Celsius)
ΔT = change in temperature (in degrees Celsius)
In this case, you have the following information:
Q = 240 J
m = 5 g
ΔT = 200 °C
First, convert the mass from grams to kilograms:
m = 5 g = 0.005 kg
Next, rearrange the formula to solve for c:
c = Q / (m * ΔT)
Substitute the given values into the equation:
c = 240 J / (0.005 kg * 200 °C)
Simplify the equation:
c = 240 J / (0.001 kg * °C)
Finally, calculate the specific heat:
c = 240,000 J / kg °C
So, the specific heat of the metal is 240,000 J/kg°C.