Dinitrogen oxide (or nitrous oxide), N20, also known as laughing gas, is widely used as an anesthetic in dentistry.

How many moles are in 27.4 g of dinitrogen oxide?
Express your answer with the appropriate units.

To find the number of moles in 27.4 g of dinitrogen oxide, we need to use the molar mass of N2O.

The molar mass of N2O is calculated by adding the atomic masses of nitrogen (N) and oxygen (O):

Molar mass of N2O = 2(atomic mass of N) + atomic mass of O
= 2(14.01 g/mol) + 16.00 g/mol
= 28.02 g/mol + 16.00 g/mol
= 44.02 g/mol

Now, we can use the molar mass to calculate the number of moles:

Number of moles = Mass / Molar mass
= 27.4 g / 44.02 g/mol
≈ 0.623 mol

So, there are approximately 0.623 moles in 27.4 g of dinitrogen oxide.

To determine the number of moles in 27.4 g of dinitrogen oxide (N2O), we need to use the formula:

moles = mass (in grams) / molar mass (in grams per mole)

First, let's find the molar mass of dinitrogen oxide (N2O).

The molar mass of nitrogen (N) is approximately 14.01 g/mol. Since there are two nitrogen atoms in dinitrogen oxide, the total mass for nitrogen is 2 * 14.01 g/mol = 28.02 g/mol.

The molar mass of oxygen (O) is approximately 16.00 g/mol.

Adding the masses of nitrogen and oxygen together, the molar mass of dinitrogen oxide (N2O) is 28.02 g/mol + 16.00 g/mol = 44.02 g/mol.

Now we can calculate the number of moles:

moles = 27.4 g / 44.02 g/mol = 0.623 moles.

Therefore, there are 0.623 moles in 27.4 g of dinitrogen oxide.

To find the number of moles in a given mass of dinitrogen oxide (N2O), we need to use the formula:

Number of moles = Mass / Molar mass

The molar mass of N2O can be obtained by adding up the atomic masses of each element present in the compound:

Molar mass of N = 14.01 g/mol
Molar mass of O = 16.00 g/mol

Molar mass of N2O = 2(N) + 1(O) = 2(14.01 g/mol) + 16.00 g/mol = 44.02 g/mol

Now, we can substitute the mass and molar mass values into the formula:

Number of moles = 27.4 g / 44.02 g/mol

Dividing these values, we get:

Number of moles = 0.623 mol

Therefore, there are 0.623 moles in 27.4 g of dinitrogen oxide (N2O), and the answer should be expressed as:

0.623 mol (moles)