Dinitrogen oxide (or nitrous oxide), N20, also known as laughing gas, is widely used as an anesthetic in dentistry.
How many grams are in 1.40 moles of dinitrogen oxide?
Express your answer with the appropriate units.
To convert moles to grams, we need to use the molar mass of dinitrogen oxide (N20).
The molar mass of N20 is calculated by adding the atomic masses of nitrogen (N) and oxygen (O).
Molar mass of N: 14.01 g/mol
Molar mass of O: 16.00 g/mol
Molar mass of N20 = (2 * Molar mass of N) + Molar mass of O
= (2 * 14.01 g/mol) + 16.00 g/mol
= 28.02 g/mol + 16.00 g/mol
= 44.02 g/mol
Now, we can calculate the grams in 1.40 moles of dinitrogen oxide:
Grams = Moles * Molar mass
= 1.40 moles * 44.02 g/mol
= 61.636 g
Therefore, there are 61.636 grams in 1.40 moles of dinitrogen oxide.
To determine the number of grams in 1.40 moles of dinitrogen oxide (N2O), we need to use the molar mass of the compound.
The molar mass of dinitrogen oxide is calculated by adding the atomic masses of nitrogen (N) and oxygen (O) in the compound.
Molar mass of N2O = (2 * atomic mass of nitrogen) + atomic mass of oxygen
= (2 * 14.007) + 15.999
= 44.013 g/mol
Now we can calculate the number of grams:
Number of grams = Number of moles * Molar mass
= 1.40 mol * 44.013 g/mol
= 61.62 g
Therefore, there are 61.62 grams in 1.40 moles of dinitrogen oxide (N2O).
To determine the number of grams in 1.40 moles of dinitrogen oxide (N2O), we need to use the molar mass of N2O.
The molar mass of N2O can be calculated by finding the sum of the atomic masses of each individual atom in N2O.
N2O consists of two nitrogen atoms (N) and one oxygen atom (O). The atomic masses of nitrogen and oxygen are approximately 14.01 g/mole and 16.00 g/mole, respectively.
So, the molar mass of N2O is calculated as follows:
Molar mass of N2O = (2 * molar mass of N) + (1 * molar mass of O)
= (2 * 14.01 g/mole) + (1 * 16.00 g/mole)
= 28.02 g/mole + 16.00 g/mole
= 44.02 g/mole
Now, we can use the molar mass of N2O to calculate the grams in 1.40 moles.
Grams = moles * molar mass
= 1.40 moles * 44.02 g/mole
= 61.63 grams
Therefore, there are 61.63 grams of dinitrogen oxide in 1.40 moles.
Answer: 61.63 grams