How many grams of carbon are in 5.28 g of butyric acid?
Express your answer to three significant figures and include the appropriate units.
The molar mass of butyric acid (C4H8O2) can be calculated by summing the atomic masses of the constituent elements:
(4 * 12.01 g/mol) + (8 * 1.01 g/mol) + (2 * 16.00 g/mol) = 88.11 g/mol
To find the number of moles of butyric acid in 5.28 g, we divide the mass by the molar mass:
5.28 g / 88.11 g/mol = 0.0599 mol
Since there is one carbon atom in each molecule of butyric acid, the number of grams of carbon is equal to the molar mass of carbon:
1 * 12.01 g/mol = 12.01 g
To find the mass of carbon in 0.0599 mol of butyric acid, we multiply the number of moles by the molar mass of carbon:
0.0599 mol * 12.01 g/mol = 0.719 g
Therefore, there are 0.719 grams of carbon in 5.28 g of butyric acid.
To determine the number of grams of carbon in 5.28 g of butyric acid, we first need to find the molar mass of butyric acid (C4H8O2).
C = 12.01 g/mol
H = 1.008 g/mol
O = 16.00 g/mol
Molar mass of C4H8O2:
(4 * C) + (8 * H) + (2 * O)
= (4 * 12.01 g/mol) + (8 * 1.008 g/mol) + (2 * 16.00 g/mol)
= 48.04 g/mol + 8.064 g/mol + 32.00 g/mol
= 88.104 g/mol
To find the mass of carbon, we need to know the ratio of carbon to butyric acid. From the chemical formula, we can see that there are 4 moles of carbon in 1 mole of butyric acid.
Mass of carbon = (4 moles of carbon / 1 mole of butyric acid) * (molar mass of butyric acid)
= (4 mol C / 1 mol C4H8O2) * 88.104 g/mol
= 352.416 g
Therefore, there are 352 grams of carbon in 5.28 grams of butyric acid.
To determine the number of grams of carbon in 5.28 g of butyric acid, we need to know the molecular formula of butyric acid and its molar mass.
The molecular formula of butyric acid is C4H8O2, which means each molecule of butyric acid contains 4 carbon atoms (C).
To calculate the molar mass of butyric acid, we need to multiply the atomic mass of each element by the number of atoms of that element in the molecular formula and sum them up.
The atomic mass of carbon (C) is approximately 12.01 g/mol.
The molar mass of butyric acid is therefore:
(4 * 12.01 g/mol) + (8 * 1.01 g/mol) + (2 * 16.00 g/mol) = 88.11 g/mol (rounded to two decimal places).
Now we can use this molar mass to calculate the grams of carbon in 5.28 g of butyric acid.
First, find the moles of butyric acid in 5.28 g by dividing the mass by the molar mass:
moles = mass / molar mass = 5.28 g / 88.11 g/mol ≈ 0.06 mol (rounded to two decimal places).
Since each mole of butyric acid contains 4 moles of carbon (according to the molecular formula), multiply the number of moles of butyric acid by 4 to obtain the moles of carbon:
moles of carbon = 0.06 mol * 4 = 0.24 mol.
Finally, convert moles of carbon to grams by multiplying by the molar mass of carbon:
grams of carbon = moles of carbon * molar mass of carbon = 0.24 mol * 12.01 g/mol ≈ 2.88 g (rounded to three significant figures).
Therefore, there are approximately 2.88 grams of carbon in 5.28 grams of butyric acid.