A pushing force of 7 N to the right is applied to a book on a table. A frictional force of 3 N is applied in the opposite direction.
In which direction will the book move?
(1 point)
The book will stay stationary.
More information is needed.
The book will move to the left.
The book will move to the right.
The net force acting on the book is the difference between the pushing force and the frictional force.
Net force = Pushing force - Frictional force
Net force = 7 N - 3 N
Net force = 4 N to the right
Since the net force is to the right, the book will move to the right.
Therefore, the correct answer is: The book will move to the right.
The book will move to the right.
To determine the direction in which the book will move, we need to consider the net force acting on it. The net force is the vector sum of all the forces acting on the book.
In this case, there are two forces acting on the book: the pushing force of 7 N to the right and the frictional force of 3 N in the opposite direction.
Since the frictional force is opposing the pushing force, it will act as a resistance to the book's motion.
To find the net force, we subtract the frictional force from the pushing force:
Net force = Pushing force - Frictional force
= 7 N - 3 N
= 4 N
The net force of 4 N is still in the direction of the initial pushing force (to the right). Therefore, the book will move to the right.
So, the correct answer is:
The book will move to the right.