A chemist took several small beakers of solution and combined them in a large pitcher. He poured in 317.59 milliliters from the first beaker, 34.75 milliliters from the next beaker, and 16.3 milliliters from the third beaker. How many milliliters of the solution did the chemist put in the pitcher?
The chemist put in a total of 317.59 + 34.75 + 16.3 = <<317.59+34.75+16.3=368.64>>368.64 milliliters of the solution. Answer: \boxed{368.64}.
To find the total volume of the solution that the chemist put in the pitcher, we need to add the volumes from each beaker.
The volume poured from the first beaker is 317.59 milliliters.
The volume poured from the second beaker is 34.75 milliliters.
The volume poured from the third beaker is 16.3 milliliters.
To find the total volume, we add these three values:
317.59 mL + 34.75 mL + 16.3 mL = 368.64 mL
Therefore, the chemist put 368.64 milliliters of the solution in the pitcher.
To find the total volume of solution the chemist put in the pitcher, we need to add the volumes from each beaker.
First, we add the volume from the first beaker, which is 317.59 milliliters.
Next, we add the volume from the next beaker, which is 34.75 milliliters.
Finally, we add the volume from the third beaker, which is 16.3 milliliters.
Adding them together, we get: 317.59 + 34.75 + 16.3 = 368.64 milliliters.
Therefore, the chemist put 368.64 milliliters of solution in the pitcher.