A man saves 2,000 naira in four banks in the proportion 4:3:2:1, How much does he save in the bank with the largest amount
To find the amount saved in the bank with the largest amount, we need to determine the ratio of the amounts saved in each of the four banks.
The total sum of the ratios is 4+3+2+1 = 10.
Let's assume the amount saved in the largest bank is 4x.
Using the ratio, we can determine the amount saved in each bank as follows:
Bank 1: 4/10 * 2000 = 800 naira
Bank 2: 3/10 * 2000 = 600 naira
Bank 3: 2/10 * 2000 = 400 naira
Bank 4: 1/10 * 2000 = 200 naira
Therefore, the man saves 800 naira in the bank with the largest amount.
To find out how much the man saves in the bank with the largest amount, we need to determine the total amount saved in the four banks.
Let's assume the amounts saved in the four banks are:
Bank 1: 4x
Bank 2: 3x
Bank 3: 2x
Bank 4: x
The sum of these amounts is given as 2,000 naira:
4x + 3x + 2x + x = 2000
Combining like terms, we get:
10x = 2000
Dividing both sides by 10, we find:
x = 200
Therefore, in the bank with the largest amount, the man saves 4x = 4 * 200 = 800 naira.
To find out how much the man saves in the bank with the largest amount, we need to calculate the total amount saved in the four banks.
Let's denote the amount saved in the banks as follows:
Bank 1: 4x
Bank 2: 3x
Bank 3: 2x
Bank 4: x
The total amount saved is the sum of the amounts saved in each bank:
Total = 4x + 3x + 2x + x = 10x
From the given information, we know that the total amount saved is 2,000 naira. Therefore:
10x = 2,000
To find the value of x, divide both sides of the equation by 10:
x = 2,000 / 10 = 200
Now we can find the amount saved in the bank with the largest amount, which is Bank 1:
Amount saved in Bank 1 = 4x = 4 * 200 = 800 naira
So, the man saves 800 naira in the bank with the largest amount.