Physics

A ball is thrown vertically upward with a speed of 1.53 m/s from a point 4.21 m above the ground. Calculate the time in which the ball will reach the ground.

{Distance Above Ground} = D = (4.21) + (1.53)*t + (1/2)*(-9.8)*t^2

{D = 0} ----> {Time To Reach Ground} = 1.096 sec

Is this right?

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  1. I didn't check your math, but the equation is right. Do this: put the answer in the google search window to calculate it .
    (4.21) + (1.53)*1.096 + (1/2)*(-9.8)*(1.096)^2

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    bobpursley
  2. Listen to my song BOP hit up da likes

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