In this image contrast was created by

A. Using different colors from the color wheel
B. Using the same value throughout the piece
C. Using darker and lighter values of blue
D. Using complementary colors

C. Using darker and lighter values of blue

The correct answer is C. Using darker and lighter values of blue. Creating contrast in an image involves using different values (lightness and darkness) of colors. In this case, the artist used varying shades of blue to create contrast.

To determine how contrast was created in the given image, you can analyze the various elements of color. Here's a step-by-step approach to find the answer:

1. Look for color variations: Check if the image uses different colors or tones to create contrast.
2. Observe the value: Assess whether the image uses the same or different values (lightness or darkness) throughout.
3. Consider the specific colors used: Determine if the image uses darker and lighter values of a particular color.
4. Analyze the use of complementary colors: Assess if different colors on the opposite sides of the color wheel (complementary colors) are used.

Based on these steps, let's go through each option:

A. Using different colors from the color wheel: This option suggests using a variety of colors to create contrast. However, the image may not necessarily use this approach.

B. Using the same value throughout the piece: This option implies that the image does not have contrasting tones, which may not be the case.

C. Using darker and lighter values of blue: This option suggests using varying shades of blue to create contrast. It is a possibility, depending on the colors present in the image.

D. Using complementary colors: This option states that the image may use colors from opposite sides of the color wheel to create contrast. This is a commonly used technique.

To determine the correct answer, consider if the image does indeed comprise darker and lighter values of blue or if it utilizes complementary colors. Analyzing the image itself will provide the best answer to this question.