se the equation to answer the question: CH4 + 2O2 → CO2 + 2H2O If you change the 2 in front of 2O2 to a 3, what will be the change in the results on the right side of the equation? (1 point) Responses There are 3 CO2 molecules There are 3 CO 2 molecules There are 3 oxygen molecules There are 3 oxygen molecules There are now 6 water molecules There are now 6 water molecules Nothing changes in the equation.
If you change the 2 in front of 2O2 to a 3, the change in the results on the right side of the equation will be: "There are now 6 water molecules."
are you sure
Apologies for the confusion. If you change the 2 in front of 2O2 to a 3, the correct change in the results on the right side of the equation would be: "There are now 3 CO2 molecules."
which is the correct answer
I apologize for the incorrect response earlier. The correct change in the results on the right side of the equation, if you change the 2 in front of 2O2 to a 3, would be: "There are 3 CO2 molecules."
If you change the coefficient in front of 2O2 to 3, the change in the results on the right side of the equation will be:
- There will be 3 CO2 molecules instead of 2 CO2 molecules.
- There will still be 2 H2O molecules, as the coefficient in front of it remains the same.
- There will be a total of 6 oxygen molecules (3 from CO2 and 3 from H2O).
Therefore, the correct answer would be:
- There are now 3 CO2 molecules.
- There are 6 oxygen molecules.
- There are still 2 water molecules.
To answer this question, we need to understand the balanced chemical equation provided: CH4 + 2O2 → CO2 + 2H2O.
This equation shows the reaction of methane (CH4) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). The coefficients in front of each molecule represents the number of molecules involved in the reaction.
In the original equation, we see that there are 2O2 molecules, which means we have a total of 2 oxygen molecules.
If we change the coefficient in front of the oxygen (O2) from 2 to 3, the equation will become: CH4 + 3O2 → CO2 + 2H2O.
Now, let's observe the change in the results on the right side of the equation.
Initially, we had one molecule of carbon dioxide (CO2) and two molecules of water (2H2O).
With the updated equation, nothing changes for carbon dioxide (CO2) as there is no change in the coefficient in front of it. So, we still have one molecule of carbon dioxide.
But for water (H2O), there is a change. Previously, we had two molecules of water, and now we have two H2O on the right side, so we still have two molecules of water.
In conclusion, changing the coefficient in front of O2 from 2 to 3 in the equation CH4 + 2O2 → CO2 + 2H2O results in no change for carbon dioxide (CO2) and a retention of two molecules of water (H2O), so the correct answer is: Nothing changes in the equation.