How could you check to see if the point (5, 6) is the solution to the Linear System of equations?(1 point) Responses Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true. Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true. Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true. Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true. Substitute 5 in for x and 6 in for y in one of the equations to see if the equation is true. Substitute 5 in for x and 6 in for y in one of the equations to see if the equation is true. Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
To check if the point (5, 6) is the solution to the linear system of equations, you should substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
To check if the point (5, 6) is a solution to a linear system of equations, you need to substitute the x and y values of the point into both equations and see if both equations are true.
Let's say you have two equations:
Equation 1: 2x + 3y = 17
Equation 2: -4x + y = -14
To check if (5, 6) is a solution, substitute x = 5 and y = 6 into both equations:
For Equation 1: 2(5) + 3(6) = 17
Simplify: 10 + 18 = 17
This equation is not true since 10 + 18 ≠ 17.
For Equation 2: -4(5) + 6 = -14
Simplify: -20 + 6 = -14
This equation is true since -20 + 6 = -14.
Since both equations should be true for (5, 6) to be a solution, but only Equation 2 is true, we can conclude that (5, 6) is not a solution to the linear system of equations.