Consider the function,
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(
�
)
=
2
�
−
1
f(x)=2x−1
Use the above function to complete the following table.
x
f(x)
1
0
-1
2
To complete the table, we need to plug in each value of x into the function f(x) = 2x - 1.
For x = 1, f(1) = 2(1) - 1 = 2 - 1 = 1.
For x = 0, f(0) = 2(0) - 1 = 0 - 1 = -1.
For x = -1, f(-1) = 2(-1) - 1 = -2 - 1 = -3.
For x = 2, f(2) = 2(2) - 1 = 4 - 1 = 3.
Now we can complete the table:
x f(x)
1 1
0 -1
-1 -3
2 3
To complete the table, we need to substitute the given values of x into the function f(x) = 2x -1.
For x = 1:
f(1) = 2(1) - 1
f(1) = 2 - 1
f(1) = 1
For x = 0:
f(0) = 2(0) - 1
f(0) = 0 - 1
f(0) = -1
For x = -1:
f(-1) = 2(-1) - 1
f(-1) = -2 - 1
f(-1) = -3
For x = 2:
f(2) = 2(2) - 1
f(2) = 4 - 1
f(2) = 3
Completing the table:
x f(x)
1 1
0 -1
-1 -3
2 3
To complete the table using the given function f(x) = 2x - 1, we will substitute each value of x into the function and solve for f(x).
For the first row where x = 1:
f(1) = 2(1) - 1
= 2 - 1
= 1
So, when x = 1, f(x) is equal to 1.
For the second row where x = 0:
f(0) = 2(0) - 1
= 0 - 1
= -1
So, when x = 0, f(x) is equal to -1.
For the third row where x = -1:
f(-1) = 2(-1) - 1
= -2 - 1
= -3
So, when x = -1, f(x) is equal to -3.
For the fourth row where x = 2:
f(2) = 2(2) - 1
= 4 - 1
= 3
So, when x = 2, f(x) is equal to 3.
Now we can fill in the table:
x | f(x)
--------------
1 | 1
0 | -1
-1 | -3
2 | 3