225/88 RA → 4/2 He+ 221/ blank Rn
The missing box would be the number ____ ? And this is a form of ____ decay?
The missing box would be the number 221. This is a form of alpha decay.
To find the missing number in the decay equation, we can use the conservation of mass and atomic number. Since the atomic number is conserved during a nuclear decay process, we can equate the atomic numbers on both sides of the equation.
Given:
225/88 RA → 4/2 He + 221/blank Rn
The atomic number of Radium (Ra) is 88. On the right side of the equation, we have an alpha particle (Helium-4), which has an atomic number of 2. Therefore, the atomic number of the missing element (Rn) is the difference between the atomic number of Ra and He:
Atomic number of Rn = Atomic number of Ra - Atomic number of He
Atomic number of Rn = 88 - 2
Atomic number of Rn = 86
Therefore, the missing box is the number 86.
This decay process is a form of Alpha decay, as indicated by the emission of an alpha particle (4/2 He).
To find the missing number in the equation 225/88 RA → 4/2 He+ 221/___ Rn, we can use the law of conservation of mass and atomic number.
In this equation, the number on the top left of each fraction represents the atomic mass, and the number on the bottom left represents the atomic number.
According to the law of conservation of mass, the sum of atomic masses must be equal on both sides of the equation. Similarly, the sum of atomic numbers must also be equal.
Let's calculate the sum of atomic masses on each side:
225 (RA atomic mass) = 4 (He atomic mass) + _____ (Rn atomic mass)
To find the value of the missing atomic mass, we can subtract 4 from 225:
225 - 4 = 221
Therefore, the missing atomic mass is 221.
Now, let's calculate the sum of atomic numbers on each side:
88 (RA atomic number) = 2 (He atomic number) + _____ (Rn atomic number)
To find the value of the missing atomic number, we can subtract 2 from 88:
88 - 2 = 86
Therefore, the missing atomic number is 86.
In conclusion, the missing box would be the number 221, and this is a form of alpha decay.