How could you check to see if the point (5, 6) is the solution to the Linear System of equations?

Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.

Substitute 5 in for x and 6 in for y in one of the equations to see if the equation is true.
Substitute 5 in for x and 6 in for y in one of the equations to see if the equation is true.

Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.
Substitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.

Substitute 6 in for x and 5 in for y in one of the equations to see if the equation is true.

Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.

To check if the point (5, 6) is the solution to a Linear System of equations, you need to substitute the values of x and y from the point into both of the equations and see if both equations are true.

Start by substituting 5 in for x and 6 in for y in the first equation. Evaluate the equation and check if it is true. Then, substitute the same values into the second equation and check if it is also true. If both equations are true, then the point (5, 6) is a solution to the Linear System of equations.

For example, let's say we have the following system of equations:

Equation 1: 2x + 3y = 22
Equation 2: 4x - y = 14

To check if (5, 6) is a solution, substitute x = 5 and y = 6 into both equations:

Equation 1: 2(5) + 3(6) = 10 + 18 = 28
Equation 2: 4(5) - 6 = 20 - 6 = 14

Since both equations are true, the point (5, 6) is indeed a solution to the Linear System of equations.

To check if the point (5, 6) is the solution to a linear system of equations, you need to substitute the values of x and y into each equation and check if both equations are true.

1. Substitute 5 in for x and 6 in for y in the first equation. Check if the equation is true.
- Example: 3x + 2y = 23
- Substitute: 3(5) + 2(6) = 23
- Calculate: 15 + 12 = 23
- Result: 27 = 23 (not true)

2. Substitute 5 in for x and 6 in for y in the second equation. Check if the equation is true.
- Example: 4x - y = 14
- Substitute: 4(5) - 6 = 14
- Calculate: 20 - 6 = 14
- Result: 14 = 14 (true)

Since the first equation is not true when substituting the values, the point (5, 6) is not the solution to the linear system of equations.