How much work is done lifting a 1.70 kg box straight up onto a shelf that is 17 m high
To find the work done in lifting the box, we need to use the formula:
Work = force × distance
The force exerted to lift the box is equal to its weight, which can be calculated using the formula:
Weight = mass × acceleration due to gravity
Assuming that acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight to be:
Weight = 1.70 kg × 9.8 m/s² = 16.66 N
Now we have the weight and the distance (17 m), so we can calculate the work:
Work = force × distance = 16.66 N × 17 m = 283.22 J
Therefore, the work done in lifting the 1.70 kg box straight up onto a shelf that is 17 m high is approximately 283.22 Joules.
To calculate the work done in lifting the box, we need to multiply the force applied by the distance moved. In this case, we need to determine the force required to lift the box and the height it is lifted.
First, let's calculate the force required to lift the box. The force applied to lift an object is equal to its weight, which can be calculated using the formula: weight = mass × gravity.
The mass of the box is given as 1.70 kg, and the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the box is:
weight = 1.70 kg × 9.8 m/s^2 = 16.66 N (rounded to two decimal places)
Now, let's calculate the work done. The work done is equal to the force applied multiplied by the distance moved. The distance moved is given as 17 m.
work = force × distance = 16.66 N × 17 m = 283.22 Joules (rounded to two decimal places)
Therefore, the amount of work done in lifting the 1.70 kg box onto a shelf that is 17 m high is approximately 283.22 Joules.
To calculate the work done, we need to use the formula:
Work = Force * Distance * cos(theta)
In this case, the force required to lift the box straight up is equal to its weight, which can be calculated using the formula:
Force = mass * gravity
Where:
- mass = 1.70 kg (given)
- gravity = 9.8 m/s^2 (acceleration due to gravity)
Let's plug in the values:
Force = 1.70 kg * 9.8 m/s^2
= 16.66 N
Now, we can calculate the work done:
Work = Force * Distance * cos(theta)
The distance is given as 17 m, and since the box is being lifted vertically, the angle (theta) between force and displacement is 0 degrees. Hence, the cosine of 0 degrees is 1.
Work = 16.66 N * 17 m * cos(0)
= 16.66 N * 17 m * 1
= 283.22 Joules
Therefore, the work done in lifting the 1.70 kg box straight up onto a shelf that is 17 m high is 283.22 Joules.