What is the momentum of a 15 kg tire rolling down a hill at 3 m/s?
5 kg • m/s
18 kg • m/s
45 kg • m/s
60 kg • m/s
The momentum of an object is given by the equation momentum = mass × velocity.
Given:
Mass = 15 kg
Velocity = 3 m/s
Using the equation, we have:
Momentum = 15 kg × 3 m/s = 45 kg • m/s
Therefore, the momentum of the tire rolling down the hill is 45 kg • m/s.
To calculate the momentum of the tire, we can use the formula:
Momentum (p) = mass (m) x velocity (v)
Given:
Mass (m) = 15 kg
Velocity (v) = 3 m/s
Calculating the momentum:
Momentum (p) = 15 kg x 3 m/s
= 45 kg • m/s
Therefore, the momentum of the 15 kg tire rolling down a hill at 3 m/s is 45 kg • m/s.
Two objects with different masses and different velocities have the same momentum. What must be true of the velocity of the more massive object?
The more massive object has a faster velocity than the less massive object.
The more massive object has a slower velocity than the less massive object.
The more massive object has the same velocity as the less massive object.
The more massive object has a slower velocity than the less massive object. This is because momentum is directly proportional to mass and velocity. If two objects have the same momentum but different masses, the object with greater mass must have a lower velocity to compensate for the difference in mass and maintain the same overall momentum.
Complete the statements about the law of conservation of momentum.
The law of conservation of momentum states that the total momentum of interacting objects does not
. This means the total momentum
a collision or explosion is equal to the total momentum
a collision or explosion.
The law of conservation of momentum states that the total momentum of interacting objects does not change. This means the total momentum before a collision or explosion is equal to the total momentum after a collision or explosion.
In the top row labeled Before Collision, two train cars approach one another with a grey arrow pointing to each car. The left car has below it m subscript 1 = 600 kilograms v subscript 1 = 4 meters per second. The right car has below it m subscript 2 = 400 kilograms v subscript 2 = -2 meters per second. In the bottom row labeled After Collision, two train cars move away from one another with a grey arrow pointing away from each car. a
Consider a system to be two train cars traveling toward each other.
What is the total momentum of the system before the train cars collide?
kg • m/s
What must the total momentum of the system be after the train cars collide?
kg • m/s
To determine the total momentum of the system before the train cars collide, we need to calculate the individual momenta of each train car and then add them together.
Given:
mass of car 1 (m1) = 600 kg
velocity of car 1 (v1) = 4 m/s
mass of car 2 (m2) = 400 kg
velocity of car 2 (v2) = -2 m/s
The momentum of an object is given by the formula momentum = mass × velocity.
Therefore, the momentum of car 1 is: momentum1 = m1 × v1 = 600 kg × 4 m/s = 2400 kg • m/s
The momentum of car 2 is: momentum2 = m2 × v2 = 400 kg × -2 m/s = -800 kg • m/s
The total momentum of the system before the train cars collide is the sum of the individual momenta:
Total momentum before collision = momentum1 + momentum2 = 2400 kg • m/s + (-800 kg • m/s)
= 1600 kg • m/s
To determine the total momentum of the system after the train cars collide, we need more information. Could you provide the masses and velocities of the train cars after the collision?
SO FOR THIS: To determine the total momentum of the system before the train cars collide, we need to calculate the individual momenta of each train car and then add them together.
Given:
mass of car 1 (m1) = 600 kg
velocity of car 1 (v1) = 4 m/s
mass of car 2 (m2) = 400 kg
velocity of car 2 (v2) = -2 m/s
The momentum of an object is given by the formula momentum = mass × velocity.
Therefore, the momentum of car 1 is: momentum1 = m1 × v1 = 600 kg × 4 m/s = 2400 kg • m/s
The momentum of car 2 is: momentum2 = m2 × v2 = 400 kg × -2 m/s = -800 kg • m/s
The total momentum of the system before the train cars collide is the sum of the individual momenta:
Total momentum before collision = momentum1 + momentum2 = 2400 kg • m/s + (-800 kg • m/s)
= 1600 kg • m/s
To determine the total momentum of the system after the train cars collide, we need more information. Could you provide the masses and velocities of the train cars after the collision?
(it's just 1,600? it's supposed to be only 1,600)