Audrina reads 30 pages that is 10 pages more than half of the pages Taylor reads how many pages did Taylor read write an equation in the form PX + p = r to represent this problem

Let X represent the number of pages Taylor reads.

Half of the pages Taylor reads: X/2

10 pages more than half of the pages Taylor reads: (X/2) + 10

Audrina reads 30 pages, so we can set up the equation:

(X/2) + 10 = 30

Multiplying through by 2 to eliminate the fraction:

X + 20 = 60

Subtracting 20 from both sides:

X = 40

Therefore, Taylor read 40 pages.

The equation in the form "PX + p = r" is:

1X + 20 = 60

Let's say the number of pages Taylor reads is represented by the variable "T". The problem states that Audrina reads 10 pages more than half of the pages Taylor reads.

Half of the pages Taylor reads is expressed as (1/2)T. We then add 10 pages to that to represent the number of pages Audrina reads. So, Audrina reads (1/2)T + 10 pages.

Given that Audrina reads 30 pages, we can set up the equation:

(1/2)T + 10 = 30

To rewrite this equation in the form PX + p = r, we simplify it a bit:

(1/2)T = 30 - 10
(1/2)T = 20

Now, we can multiply both sides of the equation by 2 to isolate T:

2 * (1/2)T = 2 * 20
T = 40

Therefore, Taylor read 40 pages.

The equation in the requested form is:
(1/2)T + 10 = 30

To solve this problem, we need to set up an equation using the given information.

Let's assume that Taylor read X pages. According to the problem, Audrina reads 10 pages more than half of the pages Taylor reads. Therefore, Audrina read (X/2) + 10 pages.

The total number of pages Audrina reads is given as 30. So, the equation in the form PX + p = r can be written as:

(X/2) + 10 = 30

Now, we can solve this equation to find the value of X, which represents the number of pages Taylor read.

To isolate the term containing X, we subtract 10 from both sides of the equation:

(X/2) = 30 - 10
(X/2) = 20

Next, multiply both sides of the equation by 2 to eliminate the fraction:

2 * (X/2) = 2 * 20
X = 40

Therefore, Taylor read 40 pages.

Wrong

Apologies for the incorrect response. Let's solve the problem correctly.

Let's assume the number of pages Taylor reads is represented by the variable "T".

According to the problem, Audrina reads 10 pages more than half of the pages Taylor reads. Therefore, Audrina read (1/2)T + 10 pages.

The total number of pages Audrina reads is given as 30. So, the equation in the form PX + p = r can be written as:

(1/2)T + 10 = 30

To isolate the term containing T, we subtract 10 from both sides of the equation:
(1/2)T = 30 - 10
(1/2)T = 20

Next, to get rid of the fraction, we can multiply both sides of the equation by 2:
2 * (1/2)T = 2 * 20
T = 40

Therefore, Taylor read 40 pages.

So, the correct equation in the form PX + p = r is:
(1/2)T + 10 = 30

Step by step bot

Apologies for the confusion earlier. Let's solve the problem step by step correctly.

Step 1: Assign variables.
Let's assign the variable "T" to represent the number of pages Taylor reads.

Step 2: Write the equation.
The problem states that Audrina reads 10 pages more than half of the pages Taylor reads, which can be written as (1/2)T + 10.
The problem also states that Audrina reads a total of 30 pages, so we can set up the equation as follows:
(1/2)T + 10 = 30

Step 3: Simplify the equation.
To solve the equation, start by subtracting 10 from both sides to isolate the term with (1/2)T:
(1/2)T = 30 - 10
(1/2)T = 20

Step 4: Solve for T.
To get rid of the fraction, multiply both sides of the equation by 2:
2 * (1/2)T = 2 * 20
T = 40

Step 5: Interpret the solution.
The solution T = 40 means that Taylor read 40 pages.

Therefore, the equation in the requested form PX + p = r is:
(1/2)T + 10 = 30

Bot gpt 3.5

I apologize for any confusion caused. I am an AI language model based on OpenAI's GPT-3. While I strive to provide accurate and helpful responses, there may be instances where the answer may not align with the intended solution. If you have any further questions or need assistance with any other problem, please let me know and I'll be happy to help.

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