A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks. (4 points) a) An equation for the total cars and trucks for Dealership A: x + y = 225 b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300 c) How many cars did Dealership A sell? 125 d) Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell? 50
The equation for the total cars and trucks for Dealership A is x + y = 225, where x represents the number of cars sold and y represents the number of trucks sold.
The equation for the total cars and trucks for Dealership B is 2x + 1/2y = 300.
Since Dealership B sold twice as many cars as Dealership A, the value of x for Dealership B would be twice the value of x for Dealership A. So, x = 2 * 125 = 250.
Given that Dealership B sold half as many trucks as Dealership A, the value of y for Dealership B would be half the value of y for Dealership A. So, y = 1/2 * 50 = 25.
Therefore, Dealership A sold 125 cars and Dealership B sold 25 trucks.
a) An equation for the total cars and trucks for Dealership A can be represented as:
x + y = 225
where x represents the number of cars sold and y represents the number of trucks sold.
b) An equation for the total cars and trucks for Dealership B can be represented as:
2x + (1/2)y = 300
where 2x represents twice the number of cars sold by Dealership A and (1/2)y represents half the number of trucks sold by Dealership A.
c) From the given information, it is stated that Dealership A sold a total of 225 cars and trucks. Therefore, we can find the value of x (number of cars sold by Dealership A) by substituting this information into equation (a):
x + y = 225
x + y = 225
x + y = 225
x = 225 - y
x = 225 - y
x = 225 - y
x = 225 - y
x = 125
Therefore, Dealership A sold 125 cars.
d) It is stated that Dealership B sold half as many trucks as Dealership A. Since Dealership A sold y trucks, Dealership B sold (1/2)y trucks. Thus, we can represent equation (b) as:
2x + (1/2)y = 300
2(125) + (1/2)y = 300
250 + (1/2)y = 300
(1/2)y = 300 - 250
(1/2)y = 50
y = 50 * 2
y = 100
Therefore, Dealership B sold 100 trucks.
To solve this problem, we can use the given information and set up equations to represent the number of cars and trucks sold by each dealership.
a) An equation for the total cars and trucks for Dealership A:
Let x be the number of cars sold by Dealership A, and y be the number of trucks sold by Dealership A. The total number of cars and trucks sold by Dealership A is 225. So, we can set up the equation:
x + y = 225
b) An equation for the total cars and trucks for Dealership B:
Given that Dealership B sold twice as many cars as Dealership A and half as many trucks, let's represent this:
Dealership B sold 2x cars and 1/2y trucks. The total number of cars and trucks sold by Dealership B is 300. So, we can set up the equation:
2x + 1/2y = 300
c) To find the number of cars sold by Dealership A, we can use the equation from part (a):
x + y = 225
Since we are looking for the number of cars sold by Dealership A, we set the value of y (number of trucks sold by Dealership A) to zero. Thus, the equation becomes:
x + 0 = 225
x = 225
Therefore, Dealership A sold 225 cars.
d) Given that Dealership B sold half as many trucks as Dealership A, we can substitute the value of y (number of trucks sold by Dealership A) into the equation from part (b):
2x + 1/2y = 300
Since Dealership B sold half as many trucks as Dealership A, the value of y is half of the number of trucks sold by Dealership A. Thus, the equation becomes:
2x + 1/2(2y) = 300
2x + y = 300
To find the value of y (number of trucks sold by Dealership B), we need to solve this equation. From part (c), we know that x = 225. Substituting this value into the equation:
2(225) + y = 300
450 + y = 300
y = 300 - 450
y = -150
Therefore, Dealership B sold -150 trucks. However, this result is not possible in a real scenario. It seems like there might be a mistake or inconsistency in the given information.
Please double-check the problem statement or provide additional information if needed.
are you sure
Apologies for the confusion. Let's double-check the calculations and solve the problem correctly.
a) We are given that Dealership A sold a total of 225 cars and trucks. Therefore, we can set up the equation:
x + y = 225
b) Dealership B sold twice as many cars as Dealership A and half as many trucks. So, we have:
2x + (1/2)y = 300
c) To find the number of cars sold by Dealership A, we can use the equation from part a:
x + y = 225
Since we are interested in the number of cars sold by Dealership A, we set y (number of trucks sold by Dealership A) to zero. The equation becomes:
x + 0 = 225
x = 225
Therefore, Dealership A sold 225 cars.
d) Given that Dealership B sold half as many trucks as Dealership A, we can substitute the value of y (number of trucks sold by Dealership A) into the equation from part b:
2x + (1/2)y = 300
Since Dealership B sold half as many trucks as Dealership A, y is half of the number of trucks sold by Dealership A. The equation becomes:
2x + (1/2)(2y) = 300
2x + y = 300
To find the value of y (number of trucks sold by Dealership B), we need to solve this equation. From part c, we know that x = 225. Substituting this value into the equation:
2(225) + y = 300
450 + y = 300
y = 300 - 450
y = -150
Therefore, Dealership B sold -150 trucks. However, this result is not possible in a real scenario. There seems to be a mistake or inconsistency in the given information.
I apologize for any confusion caused. Please double-check the problem statement or provide additional information if needed.
Dealership a sold 125 cars and 100 trucks if dealership b sold twice as many cars than dealership a and half as many trucks than dealership a how many cars and trucks did dealer ship b sold
Given that Dealership A sold 125 cars and 100 trucks, we know that x (the number of cars sold by Dealership A) is 125 and y (the number of trucks sold by Dealership A) is 100.
We are also told that Dealership B sold twice as many cars as Dealership A and half as many trucks. Therefore, the number of cars sold by Dealership B is 2 times the number of cars sold by Dealership A, which is 2 * 125 = 250.
The number of trucks sold by Dealership B is half the number of trucks sold by Dealership A, which is 1/2 * 100 = 50.
Therefore, Dealership B sold 250 cars and 50 trucks.
correct if anyone asks you the question at the top give them these answers A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks. (4 points) a) An equation for the total cars and trucks for Dealership A: x + y = 225 b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300 c) How many cars did Dealership A sell? 125 d) Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell? 50
a) An equation for the total cars and trucks for Dealership A: x + y = 225
b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300
c) Dealership A sold 125 cars.
d) Dealership B sold 50 trucks.