Jorge’s starting annual salary is $36,500. At the beginning of each new year, he receives a $2,375 raise. Write an explicit formula to represent his salary after n years. What will his salary be after 15 years?

(1 point)
Responses

lower a subscript n baseline equals 2,375 plus 36,500 left parenthesis n minus 1 right parenthesis; $69,750
Image with alt text: lower a subscript n baseline equals 2,375 plus 36,500 left parenthesis n minus 1 right parenthesis ; $69,750

lower a subscript n baseline equals 36,500 plus 2,375 left parenthesis n minus 1 right parenthesis; $69,750
Image with alt text: lower a subscript n baseline equals 36,500 plus 2,375 left parenthesis n minus 1 right parenthesis ; $69,750

lower a subscript n baseline equals 2,375 plus 36,500 left parenthesis n minus 1 right parenthesis; $72,125
Image with alt text: lower a subscript n baseline equals 2,375 plus 36,500 left parenthesis n minus 1 right parenthesis ; $72,125

lower a subscript n baseline equals 36,500 plus 2,375 left parenthesis n minus 1 right parenthesis; $72,125

The correct answer is:

\[a_n = 2,375 + 36,500(n-1)\]

His salary after 15 years can be found by substituting n = 15 into the formula:

\[a_{15} = 2,375 + 36,500(15-1) = 2,375 + 36,500(14) = \$69,750\]

So his salary after 15 years will be $69,750.

The correct explicit formula to represent Jorge's salary after n years is:

Salary(n) = 2,375 + 36,500(n - 1)

To find his salary after 15 years, plug the value of n = 15 into the formula:

Salary(15) = 2,375 + 36,500(15 - 1)
= 2,375 + 36,500(14)
= 2,375 + 511,000
= $513,375

Therefore, his salary after 15 years will be $513,375.

The explicit formula to represent Jorge's salary after n years is:

Salary after n years = $36,500 + $2,375 * (n - 1)

To find his salary after 15 years, substitute n = 15 into the formula:

Salary after 15 years = $36,500 + $2,375 * (15 - 1)
= $36,500 + $2,375 * 14
= $36,500 + $33,250
= $69,750

Therefore, Jorge's salary after 15 years will be $69,750.

So, the correct option is:
Lower a subscript n equals 2,375 plus 36,500 times n minus 1; $69,750.