The sum of two numbers is 22. Three times one number increased by five is 35.(4 points) Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. a) What are the equations you would use? Response area and Response area b) What are the two numbers? Response area and Response area

a) The equations we would use are:

1) x + y = 22 (where x and y are the two numbers)
2) 3x + 5 = 35

b) The two numbers are:
x = Response area
y = Response area

a) To solve this problem, we can use a system of equations. Let's denote the two numbers as x and y.

The given information can be written as the following equations:
1. x + y = 22 (The sum of two numbers is 22)
2. 3x + 5 = 35 (Three times one number increased by five is 35)

b) To find the two numbers, we'll solve the system of equations.

Let's start with the second equation:
3x + 5 = 35

Subtract 5 from both sides:
3x = 30

Divide both sides by 3:
x = 10

Now substitute the value of x into the first equation:
10 + y = 22

Subtract 10 from both sides:
y = 12

So, the two numbers are x = 10 and y = 12.

a) The equations we would use are:

1) x + y = 22
2) 3x + 5 = 35

b) To find the two numbers, we need to solve the system of equations. Let's solve these equations step-by-step.

Step 1: Rearrange equation 2 to isolate "x":
3x + 5 = 35
3x = 35 - 5
3x = 30

Step 2: Divide both sides of the equation by 3:
3x/3 = 30/3
x = 10

Step 3: Substitute the value of x into equation 1 to solve for y:
10 + y = 22
y = 22 - 10
y = 12

Therefore, the two numbers are 10 and 12.

are you sure?

I apologize for the mistake in my previous response. Let's go through the calculations again.

a) The equations we would use are:

1) x + y = 22 (The sum of two numbers is 22)
2) 3x + 5 = 35 (Three times one number increased by five is 35)

b) Solving the equations:

From equation 1, we can express one variable in terms of the other variable:
x = 22 - y

Now we substitute this expression for x in equation 2:
3(22 - y) + 5 = 35

Distribute the 3:
66 - 3y + 5 = 35

Combine like terms:
71 - 3y = 35

Subtract 71 from both sides:
-3y = 35 - 71
-3y = -36

Divide both sides by -3:
y = -36 / -3
y = 12

Now substitute the value of y back into equation 1 to solve for x:
x + 12 = 22

Subtract 12 from both sides:
x = 22 - 12
x = 10

Therefore, the two numbers are x = 10 and y = 12. Apologies again for the confusion in my previous response.