Find the second, fourth, and tenth terms of the sequence described by the rule.
A(n) = 3 + (n - 1)(4); A(2) = (Simplify your answer. Type an integer or a decimal .)
To find the second term, we plug in n=2 into the formula for A(n):
A(2) = 3 + (2 - 1)(4)
A(2) = 3 + 1(4)
A(2) = 3 + 4
A(2) = 7
So the second term is 7.
To find the fourth term, we plug in n=4 into the formula for A(n):
A(4) = 3 + (4 - 1)(4)
A(4) = 3 + 3(4)
A(4) = 3 + 12
A(4) = 15
So the fourth term is 15.
To find the tenth term, we plug in n=10 into the formula for A(n):
A(10) = 3 + (10 - 1)(4)
A(10) = 3 + 9(4)
A(10) = 3 + 36
A(10) = 39
So the tenth term is 39.
To find the second, fourth, and tenth terms of the sequence, we can substitute the given values of n into the rule.
The rule is represented by A(n) = 3 + (n - 1)(4).
To find the second term (A(2)), we substitute n = 2 into the rule:
A(2) = 3 + (2 - 1)(4)
A(2) = 3 + 1(4)
A(2) = 3 + 4
A(2) = 7
Therefore, the second term of the sequence is 7.
To find the fourth term, we substitute n = 4 into the rule:
A(4) = 3 + (4 - 1)(4)
A(4) = 3 + 3(4)
A(4) = 3 + 12
A(4) = 15
Therefore, the fourth term of the sequence is 15.
To find the tenth term, we substitute n = 10 into the rule:
A(10) = 3 + (10 - 1)(4)
A(10) = 3 + 9(4)
A(10) = 3 + 36
A(10) = 39
Therefore, the tenth term of the sequence is 39.
In summary, the second term is 7, the fourth term is 15, and the tenth term is 39.
To find the second term of the sequence, we substitute n = 2 into the rule:
A(2) = 3 + (2 - 1)(4)
A(2) = 3 + 1(4)
A(2) = 3 + 4
A(2) = 7
So, the second term of the sequence is 7.
To find the fourth term of the sequence, we substitute n = 4 into the rule:
A(4) = 3 + (4 - 1)(4)
A(4) = 3 + 3(4)
A(4) = 3 + 12
A(4) = 15
So, the fourth term of the sequence is 15.
To find the tenth term of the sequence, we substitute n = 10 into the rule:
A(10) = 3 + (10 - 1)(4)
A(10) = 3 + 9(4)
A(10) = 3 + 36
A(10) = 39
So, the tenth term of the sequence is 39.