Find the width of a rectangle with a perimeter of 90 and a length of 15. Draw and label the rectangle first to set up your problem. (1 point) Responses 90 90 15 15 45 45 30
The width of the rectangle can be found by using the formula for the perimeter of a rectangle, which is P = 2w + 2l, where P is the perimeter, w is the width, and l is the length.
Given that the perimeter is 90 and the length is 15, we can substitute these values into the formula to solve for the width:
90 = 2w + 2(15)
90 = 2w + 30
2w = 90 - 30
2w = 60
w = 60/2
w = 30
Therefore, the width of the rectangle is 30 units.
Here is a labeled diagram of the rectangle:
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| 15 |
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The rectangle has a length of 15 units and a width of 30 units.
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To set up this problem, we need to draw a rectangle and label its dimensions.
Given:
Length = 15
We know that the perimeter of a rectangle is the sum of all its sides. In this case, the perimeter is 90.
To find the width of the rectangle, we need to consider that opposite sides of a rectangle are equal in length.
So, let's label the width as 'w'. Now, for the rectangle setup:
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| w |
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| 15 |
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Now, we can set up the equation for the perimeter:
2*(width) + 2*(length) = perimeter
Substituting the given values:
2w + 2(15) = 90
Simplifying the equation:
2w + 30 = 90
To isolate the variable, we subtract 30 from both sides of the equation:
2w = 90 - 30
2w = 60
Finally, we divide both sides of the equation by 2 to solve for 'w':
w = 60 / 2
w = 30
So, the width of the rectangle is 30.
To find the width of the rectangle, we need to use the formula for the perimeter of a rectangle, which is given by P = 2w + 2l, where P is the perimeter, w is the width, and l is the length.
Given that the perimeter is 90 units and the length is 15 units, we can set up the equation as follows:
90 = 2w + 2(15)
Simplifying the equation:
90 = 2w + 30
Subtracting 30 from both sides:
60 = 2w
Dividing by 2:
w = 30
Therefore, the width of the rectangle is 30 units.
Now, let's draw and label the rectangle:
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Length: 15 units
Width: 30 units