A rectangular park has an area of 1.36 x 10^8 ft^2. The length of the park is 1.6 x 10^4 ft. Divide the area by the length to find the width of the park
1. 8.5 x 10^3 ft
2. 8.5 x 10^4 ft
3. 8.5 x 10^2
4. 8.5 10^5
To find the width of the park, we need to divide the area by the length.
Area = 1.36 x 10^8 ft^2
Length = 1.6 x 10^4 ft
Width = Area / Length
Width = (1.36 x 10^8 ft^2) / (1.6 x 10^4 ft)
To simplify, we can divide the numbers separately and apply the exponent rule for division (subtract the exponents).
Width = (1.36 / 1.6) x 10^(8 - 4) ft
Width = 0.85 x 10^4 ft
Since 0.85 is equivalent to 8.5 x 10^(-1) (move the decimal one place to the right and increase the exponent), we can rewrite it as:
Width = 8.5 x 10^(-1) x 10^4 ft
When multiplying with the same base, we add the exponents:
Width = 8.5 x 10^(-1 + 4) ft
Width = 8.5 x 10^3 ft
Therefore, the width of the park is 8.5 x 10^3 ft.
So, the correct option is 1. 8.5 x 10^3 ft.
To find the width of the park, we can use the formula for the area of a rectangle, which is given by multiplying the length and the width of the rectangle.
Given:
Area = 1.36 x 10^8 ft^2
Length = 1.6 x 10^4 ft
To find the width, we need to divide the area by the length:
Width = Area / Length
Substituting the given values, we have:
Width = (1.36 x 10^8 ft^2) / (1.6 x 10^4 ft)
To divide these numbers in scientific notation, we can divide the coefficients (1.36 / 1.6) and subtract the exponents (8 - 4):
Width = 0.85 x 10^8-4 ft
Simplifying the exponent, we get:
Width = 0.85 x 10^4 ft
So, the width of the park is 8.5 x 10^3 ft.
Therefore, the correct option is 1. 8.5 x 10^3 ft.
To find the width of the park, we need to divide the area of the park by its length.
Area of the park = 1.36 x 10^8 ft^2
Length of the park = 1.6 x 10^4 ft
Width of the park = Area / Length
Width of the park = (1.36 x 10^8 ft^2) / (1.6 x 10^4 ft)
We can simplify this by dividing the coefficients and subtracting the exponents:
Width of the park = (1.36 / 1.6) x 10^(8 - 4) ft
Width of the park = 0.85 x 10^4 ft
Therefore, the width of the park is 8.5 x 10^3 ft. Hence, the correct answer is option 1.