What type of bond does Se and Br form? What is the name and empirical formula of the compound?
Selenium (Se) and Bromine (Br) form an ionic bond. The compound formed between Se and Br is called Selenium Bromide and its empirical formula is SeBr2.
To determine the type of bond formed between Se and Br, we need to consider their position in the periodic table.
Se belongs to Group 16 (also known as Group VI A or Chalcogens), which means it has 6 valence electrons. Br belongs to Group 17 (also known as Group VII A or Halogens), which means it has 7 valence electrons.
Both Se and Br need one more electron to complete their valence shells and achieve stability. Therefore, they will form an ionic bond by transferring one electron from Se to Br.
The resulting compound will be SeBr2. To determine its name, we use the rules for naming ionic compounds:
1. Start with the cation (the positively charged ion), which is Se in this case.
2. Write the name of the cation followed by the name of the anion (the negatively charged ion), which is bromide (Br).
3. Add the appropriate prefix if needed to indicate the number of each ion present. In this case, since only one bromide ion is present, we don't need to use a prefix.
Therefore, the compound formed from Se and Br is selenium bromide, and its empirical formula is SeBr2.
The bond formed between Se (selenium) and Br (bromine) is an ionic bond.
When an ionic bond is formed, one atom transfers electrons to another atom, resulting in the formation of positively charged cations and negatively charged anions.
In this case, bromine (Br) accepts one electron from selenium (Se) to form a single negatively charged bromide ion (Br-). As a result, selenium becomes a positively charged ion (Se2+).
The compound formed between selenium and bromine is called selenium bromide.
Since the charges of the ions involved in the compound are 2+ and 1-, respectively, the empirical formula of selenium bromide is SeBr2.