Tin (II) fluoride (SnF2) is often added to toothpaste as an ingredient to prevent tooth decay. What is the mass of F in grams and 33.7 g of the compound? Round your answer to three significant digits.
To find the mass of F in grams in 33.7 g of SnF2, we need to find the number of moles of SnF2 and then multiply it by the molar mass of F.
The molar mass of SnF2 is:
1 Sn * (atomic mass of Sn) = 1 * 118.71 g/mol = 118.71 g/mol
2 F * (atomic mass of F) = 2 * 18.998 g/mol = 37.996 g/mol
So the molar mass of SnF2 is 118.71 + 37.996 = 156.706 g/mol.
To find the moles of SnF2 in 33.7 g, we divide the mass by the molar mass:
33.7 g / 156.706 g/mol = 0.215 mol
Since there are 2 moles of F in 1 mole of SnF2, there are 0.215 mol * 2 = 0.43 mol of F in 33.7 g of SnF2.
To find the mass of F in grams, we multiply the moles of F by the molar mass of F:
0.43 mol * 18.998 g/mol = 8.187 g.
Rounded to three significant digits, the mass of F in grams in 33.7 g of SnF2 is 8.19 g.
To find the mass of F in grams in 33.7 g of SnF2, we need to determine the molar mass of SnF2 and then calculate the mass of F.
First, we need to calculate the molar mass of SnF2. The molar mass of Sn (tin) is 118.71 g/mol, and the molar mass of F (fluorine) is 18.998 g/mol (rounded to three significant digits). Since SnF2 has two fluorine atoms, we multiply the molar mass of F by 2:
Molar mass of SnF2 = molar mass of Sn + (2 × molar mass of F)
= 118.71 g/mol + (2 × 18.998 g/mol)
= 118.71 g/mol + 37.996 g/mol
= 156.706 g/mol
Now, we can calculate the mass of F in 33.7 g of SnF2. We'll use the following proportion:
mass of F (g) / mass of SnF2 (g) = molar mass of F (g/mol) / molar mass of SnF2 (g/mol)
Let's substitute the given values:
mass of F (g) / 33.7 g = 18.998 g/mol / 156.706 g/mol
To solve for the mass of F, we rearrange the equation:
mass of F (g) = (33.7 g × 18.998 g/mol) / 156.706 g/mol
Calculating this expression gives us:
mass of F (g) ≈ 4.087 g
Therefore, the mass of F in 33.7 g of SnF2 is approximately 4.087 grams (rounded to three significant digits).
To find the mass of F in 33.7 g of SnF2, we need to determine the percentage of F in the compound and then calculate the mass.
The molar mass of SnF2 can be calculated as follows:
Molar mass of Sn = 118.71 g/mol
Molar mass of F = 18.998 g/mol
Molar mass of SnF2 = (118.71 g/mol) + 2(18.998 g/mol) = 156.706 g/mol
Now, we can calculate the percentage of F in SnF2:
Percentage of F = (2 mol of F / 1 mol of SnF2) * (18.998 g/mol of F / 156.706 g/mol of SnF2) * 100
= (2/1) * (18.998/156.706) * 100
= 23.973%
To find the mass of F in 33.7 g of SnF2, we can use the calculated percentage:
Mass of F = (percentage of F / 100) * mass of SnF2
= (23.973%/100) * 33.7 g
≈ 8.09 g
Therefore, the mass of F in 33.7 g of SnF2 is approximately 8.09 grams.