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Solve the system using elimination.

2x−3y=−1
3x+4y=7

To solve the system using elimination, we need to eliminate one of the variables by adding or subtracting the equations.

To start, let's multiply the first equation by 3 and the second equation by 2 to make the coefficients of x in both equations the same:

(3)(2x - 3y) = (3)(-1)
(2)(3x + 4y) = (2)(7)

Simplifying these equations, we get:

6x - 9y = -3
6x + 8y = 14

Now we can subtract the first equation from the second equation to eliminate the x variables:

(6x + 8y) - (6x - 9y) = 14 - (-3)

Simplifying this equation, we get:

6x - 6x + 8y + 9y = 14 + 3
17y = 17
y = 1

Now that we have the value of y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:

2x - 3(1) = -1
2x - 3 = -1
2x = 2
x = 1

So the solution to the system of equations is x = 1 and y = 1.

To solve the system using elimination, the goal is to eliminate one of the variables by adding or subtracting the equations.

Given the following system of equations:
2x - 3y = -1 ...(equation1)
3x + 4y = 7 ...(equation2)

Step 1: Multiply equation 1 by 3 and equation 2 by 2 to make the coefficients of x in both equations the same:

3 * (2x - 3y) = 3 * (-1)
2 * (3x + 4y) = 2 * 7.

This simplifies the system to:

6x - 9y = -3 ...(equation3)
6x + 8y = 14 ...(equation4)

Step 2: Now, subtract equation 3 from equation 4 to eliminate the variable x:

(6x + 8y) - (6x - 9y) = 14 - (-3)
6x + 8y - 6x + 9y = 14 + 3
17y = 17
y = 1

Step 3: Substitute the value of y = 1 into equation 1 or equation 2 to solve for x.

Using equation 1:
2x - 3(1) = -1
2x - 3 = -1
2x = -1 + 3
2x = 2
x = 2/2
x = 1

Therefore, the solution to the system of equations is x = 1 and y = 1

To solve the system using elimination, we need to eliminate one variable by multiplying one (or both) of the equations by a suitable constant so that the coefficients of one variable will become opposites of each other.

Let's start by eliminating the variable "x":

Step 1: Multiply the first equation by 3 and the second equation by 2 to create opposites for the coefficients of "x":

3(2x - 3y) = 3(-1)
2(3x + 4y) = 2(7)

Step 2: Simplify the equations:

6x - 9y = -3
6x + 8y = 14

Step 3: Subtract the first equation from the second equation:

(6x + 8y) - (6x - 9y) = 14 - (-3)

Simplifying further:

6x + 8y - 6x + 9y = 14 + 3
17y = 17

Step 4: Divide both sides of the equation by 17 to solve for "y":

17y/17 = 17/17
y = 1

Step 5: Substitute the value of "y" into one of the original equations to solve for "x". Let's use the first equation:

2x - 3(1) = -1

Simplifying further:

2x - 3 = -1
2x = 2

Step 6: Divide both sides of the equation by 2 to solve for "x":

2x/2 = 2/2
x = 1

Therefore, the solution to the system of equations is x = 1 and y = 1.