An atom of helium has a mass of 6.8 x 10^-27 kg. If a room contains 9 x 10^22 atoms of helium, what is the mass of helium in the room?
To find the mass of helium in the room, we need to multiply the mass of one helium atom by the total number of helium atoms in the room.
The mass of one helium atom is given as 6.8 x 10^-27 kg.
The total number of helium atoms in the room is given as 9 x 10^22 atoms.
Multiplying these values together, we get:
(6.8 x 10^-27 kg/atom) * (9 x 10^22 atoms) = 6.12 x 10^-4 kg
Therefore, the mass of helium in the room is 6.12 x 10^-4 kg.
To find the mass of helium in the room, we can multiply the mass of a single atom of helium by the number of helium atoms.
Given:
Mass of a single helium atom = 6.8 x 10^-27 kg
Number of helium atoms in the room = 9 x 10^22
To find the mass of helium in the room, multiply the mass of a single helium atom by the number of helium atoms:
Mass of helium in the room = Mass of a single helium atom x Number of helium atoms
Substituting the given values into the formula:
Mass of helium in the room = (6.8 x 10^-27 kg) x (9 x 10^22)
Now, let's simplify the calculation:
- Multiply the coefficients: 6.8 x 9 = 61.2
- Add the powers of 10: (10^-27 kg) x (10^22) = 10^(-27 + 22) = 10^-5
Mass of helium in the room = 61.2 x 10^-5 kg
If we convert the scientific notation to decimal notation, we get:
Mass of helium in the room = 0.000612 kg
Therefore, the mass of helium in the room is 0.000612 kg.
To calculate the mass of helium in the room, you need to multiply the mass of a single atom of helium by the total number of atoms in the room.
Given:
Mass of a helium atom = 6.8 x 10^-27 kg
Number of helium atoms in the room = 9 x 10^22
To find the mass of helium in the room:
Mass of helium in the room = Mass of a single helium atom x Number of helium atoms
Mass of helium in the room = (6.8 x 10^-27 kg) x (9 x 10^22)
To multiply the numbers in scientific notation, you need to multiply the coefficients (6.8 x 9) and add the exponents (10^-27 + 10^22).
Coefficient: 6.8 x 9 = 61.2
Exponent: -27 + 22 = -5
Mass of helium in the room = 61.2 x 10^-5 kg = 6.12 x 10^-4 kg
Therefore, the mass of helium in the room is 6.12 x 10^-4 kg.