How could you check to see if the point (5, 6) is the solution to the Linear System of equations?(1 point)%0D%0AResponses%0D%0A%0D%0ASubstitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.%0D%0ASubstitute 6 in for x and 5 in for y in both of the equations to see if both equations are true.%0D%0A%0D%0ASubstitute 6 in for x and 5 in for y in one of the equations to see if the equation is true.%0D%0ASubstitute 6 in for x and 5 in for y in one of the equations to see if the equation is true.%0D%0A%0D%0ASubstitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.%0D%0ASubstitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.%0D%0A%0D%0ASubstitute 5 in for x and 6 in for y in one of the equations to see if the equation is true
The correct response would be:
Substitute 5 in for x and 6 in for y in both of the equations to see if both equations are true.
To check if the point (5, 6) is a solution to the Linear System of equations, you can substitute 5 in for x and 6 in for y in both of the equations and see if they are true.
To check if the point (5, 6) is a solution to a linear system of equations, you need to substitute the values 5 and 6 for x and y, respectively, in both equations of the system. Let's say we have two equations:
Equation 1: 2x + 3y = 12
Equation 2: 4x - 2y = 10
To check if the point (5, 6) is a solution, we substitute 5 for x and 6 for y in both equations. Let's do that:
For Equation 1:
2(5) + 3(6) = 12
10 + 18 = 12
28 = 12
For Equation 2:
4(5) - 2(6) = 10
20 - 12 = 10
8 = 10
If both equations are true after substituting the values, then the point (5, 6) is not a solution to the linear system of equations. In this case, the point (5, 6) does not satisfy either Equation 1 or Equation 2, so it is not a solution.